Pollutant Concentration and Unit Conversion

Either something is missing, or something is wrong. The two sets of units are not dimensionally consistent.

Either:

• find something that represents Joules/m³, or
• double-check the units of both quantities.

Hai Thanks for ur advise. But i checked many times the pollutants units was mentioned in nano grams/ Jol. These units exposed in the Document of KEPA Standards for The Allowed Environmental Criteria of the emission of Air from Fixed sources. here i gave u the web link. www.assekuwait.org / Links & Resources/ Kuwait EPA Legislation.pdf, Page no -340

Good evening Anjan.

Perhaps they are suggesting that the particulates(pollutants concentration) are to be in nano grams (billionths of a gram) for each Joule of Output of the device. (A joule for many of us is also called a watt second.) So you measure the mg pollution particulate actually I'm giuessing) output for a period of time, and divide by the joules (watt seconds) produced by the device for that period.

This seems to me to make perfect sense actually. The volume of the exhaust in meter^3 is hardly relevant; particulates resulting per watt second of out put ties pollution to production.

I have no advice to give regarding your sampling denominated in meter^3 to actually be toatal nanograms or mg produced. I suspect new method of sampling...

milo

Hello Milo,

How are you?

The way you describe testing the liquid and particulates, would also show the efficiency of the system also?

bb

Hi Baby bear.

There are smarter people on here than me who can answer that. And might answer it differently from me.

However, I see it as an indication of efficiency of output per pollutants emitted standpoint.

If they have to use a bunch of parasitic loads to reduce the pollutants and that reduces available output joules, then no , not necessarily more efficiently.

But from an out put of joules / nanogram of pollutants basis, yes, indeedy.

milo

We have to report lbs/MMBTU. BTU with respect to the fuel flow, so I would look to the heat content of your fuel, and clarify with your regulatory agency.

Anjan, mkruger21 is correct in that emissions are often given in mass per "heat". Determine the heating value of your fuel (for example, coal is usually around 10,000 BTU per pound; 23.242 x 10^6 J/kg -assuming I did my conversions correctly), determine the amount of fuel burned in your boiler/incinerator in kilograms, multiply to get total energy output. Multiply this by the allowable nanograms to get total emissions allowed. Convert this to milligrams and divide by the flue gas airflow (in cubic meters) to convert emissions limit to mg/m^3.