Are they on same phase ? If not (3 in 3 pghases) then of course you are on residual current.
But if they are on the same phase then why at all?
The current will not add up exactly, a lot of accuracy loss likely.
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Fantastic ideas for a Fantastic World, I make the illogical logical.They put me in cars,they put me in yer tv.They put me in stereos and those little radios you stick in your ears.They even put me in watches, they have teeny gremlins for your watches
Why don't you go straight for a single CT with 4000:5 ?
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Fantastic ideas for a Fantastic World, I make the illogical logical.They put me in cars,they put me in yer tv.They put me in stereos and those little radios you stick in your ears.They even put me in watches, they have teeny gremlins for your watches
The only situation I can think of that uses CT secondaries wired in series is for center-tapped single phase metering, which would effect the ratio of 2000:5+5 (2000:10). This method is older tech and was used to account for load usage to earth.
In your question, you have referred to a relay, and at the 4000 amp range of possible currents, I hope this is a homework question. If not, please offer a greater explanation for the reason for this question posed to us, and as many details as you can think of.
You mentioned "have to", indicating you are possibly following an engineering diagram or instructions supplied with the CT's or from some authority. If this relay is the ground fault detection provided with a switchgear of sizable capacity, you really need to have the manufacturer or a qualified engineer or technician assisting you.
We can only guess and offer assumptions with the tiny bits of information we have been given so far.
Regards, CJM
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I do not 'know it all', but i will admit that I would like to. CJM
OK, lets say we connect two 2000/5 CT secondaries in series serving an ammeter. The primary is a 1 phase bus running through both donuts. Each CT has 400 turns and the secondaries are in phase.
Therefore wouldn't we see an effective turns ratio of 800/1 or 4000/5. So, for the same 2000 amps primary on a single CT, where we would see 5 amps secondary. Now at our ammeter (with the 2 CT secondaries in series) we will see 2.5 amps.
The addition of a second identical CT in series results in the following changes (see Figure 16):
a) The bm'den (voltampere) requirement is divided between the two CTs.
b) The burden voltage capability is doubled.
c) The burden impedance placed on each CT is one-half of the external connected burden impedance.
Therefore when two CTs with similar excitation characteristics are connected in series, the excitation
voltage of each CT is reduced by 50% and the excitation cnn'ent is also reduced. The burden voltage
capability is doubled. (IEEE I EEE Std C37.110-2007)
The addition of a second identical CT in series results in the following changes (see Figure 16):
a) The bm'den (voltampere) requirement is divided between the two CTs.
b) The burden voltage capability is doubled.
c) The burden impedance placed on each CT is one-half of the external connected burden impedance.
Therefore when two CTs with similar excitation characteristics are connected in series, the excitation
voltage of each CT is reduced by 50% and the excitation cnn'ent is also reduced. The burden voltage
capability is doubled. (IEEE I EEE Std C37.110-2007)
Absolutely no idea; try asking the <...we...> instead of this forum.
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