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Participant

Join Date: Aug 2009
Posts: 2

Testing Motor Protection Circuit Breaker

08/02/2009 10:52 PM

I have a current source of 5V 1000A AC. I am unable to inject more than 100A for a 30A rating motor protection cuircuit breaker type GV2 series of schineider. Could it be due to high resistance of close circuit contacts of the motor protection circuit breaker? I collected the data sheet from the manufacturer and it does not contain the contact resistances.

If anyone has the data kindly advise me. This would help me to design a suitable test kit.

pscraja

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Guru
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Join Date: Jun 2008
Location: Alabama
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#1

Re: testing motor protection circuit breaker

08/02/2009 11:02 PM

It doesn't take much resistance to limit the current to 100 amps with only 5 volts. It could be anything and every thing in the circuit.

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#2
In reply to #1

Re: testing motor protection circuit breaker

08/03/2009 9:40 PM

Thank you for your reply. Will you please be more specific. If you want any more data I can give. Your answer is evasive "it could be anything and everything in the circuit" means nothing. Be very specific if I have to check any specific aspect.

pscraja

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Guru

Join Date: Feb 2009
Location: Houston, USA
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#3
In reply to #2

Re: testing motor protection circuit breaker

08/03/2009 10:02 PM

First try the injection set with directly shorting the terminals and see you can increase the current towards the high ampere rating (1000 A) of the set – do it carefully so that the high ampere current stays only for short time. This test tells you that the injection set is working or not.

If the injection set works, then make sure you connected the set's terminal to the relay properly with sufficient torque.

Then blame the relay.

- MS

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"All my technical advices in this forum must be consulted with and approved by a local registered professional engineer before implementation" - Mohammed Samad (Linkedin Profile: http://www.linkedin.com/in/msamad)
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Guru
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Join Date: Jun 2008
Location: Alabama
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#4

Re: Testing Motor Protection Circuit Breaker

08/04/2009 5:19 PM

pscraja

Realize that with only 0.10 ohms the limit of the amps is I = E/R = 5/0.1= 50 amps. With a resistance of 0.01 ohms the max amperage is 500 amps. That's why I said it could be anything. Since the unit is only putting out 500 amps the unit resistance is only 0.05 ohms. That will be hard to eliminate.

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msamad (1); pscraja (1); wareagle (2)

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