DC Motor Full Load Currents at 125V DC

Very simple formula for DC motor Full Load current (FLA):

FLA = (KW x 1000) / (Voltage x Efficiency)

In your case, if the efficiency of the motor is 80%

FLA = (7.5 x 1000) / (125 x 0.8) = 75 A

See the link http://www.contractorsunlimited.co.uk/toolbox/electric-motors.shtml

- MS

Thank you, it is much appreciated.

Chris.

Chris, since kW and kVA equate directly in DC, you only need to determine %efficiency to modify the 60Adc result from your stated values.

What you have asked us is stated in 'nominal' values, and you will need actual measured values to begin with. It would be of great benefit to find the manufacturer details if possible. Missing nameplates are a key indicator of used, and therefore possibly re-wound motors, so a standard table, which is readily available with a simple 'GOOGLE" is at the very least just an estimate. CJM

Thanks,

I will see if my client has any more info on this motor.

Once again thanks.

Chris, i thought I would add these links to a large number of papers on subjects related to yours, for the benefit of everyone.

The main page has a tab called 'Literature' under which the 'Technical Papers' contain a huge wealth of information related directly and indirectly to many of the common questions about controls, undocumented electric motors, transformers, power factor regulation reality (these guys make and install the real stuff) and generator related control information.

Hope this proves useful to someone, I've polished up quite a few of my own understandings at this site. It does require some searching through the 13 pages of menu, but it's well worth the effort.

Regards, CJM

Thanks for the links. I am working my way through the info there.