Horsepower Calculations

A rough guess but a 535 cubic centimetre motor, which would be 0.535 liter, would run around 5 to 30 hp depending on compression ratio and quality of fuel used. But I might be on the conservative side.

68torino

It would depend on the compression ratio of the engine and the fuel injection and atomisation characteristics as well as if there is a turbo charger at the air inlet.

the data is inadequate.

usually the power range should be 10hp and max 18 -22.

1) Add a brake to the output shaft and load it up. Measure the heat given off.

2) Add a generator to the output shaft and load it up with resistances in parallel. Measure the current and voltage for increasing loads.

3) Look at the output ratings for a Fiat Cinquecento.

For your information – my wife's Cinquecento has a 903cc engine that puts out 41bhp and 49ibft of torque. Wohoo!

And I have two ford fiestas with 999 cc CHT engines. THey output 53 horse power! Oh yeah! Let's go drifting...

The only good thing in this is that it runs about 15.5 km/l, or 6.45l/100km, or 36.46 mi/gal.

Power output from the 500 cc engine may be proportional. Stationary engines running at constant speed typically have less power, but more torque and a better fuel efficiency.

Here is a link for a Volvo marine engine, designed to run at about the speed you mention. It produces 12.2 hp.

In a different application, a 1/2 liter diesel, running at a higher rpm, could produce as much as 30 hp.

Horsepower is determined bythe rotational speed, RPM, of engine multiplied by the torque which is the power output in one revolution. A 535cc engine will produce teh sme horsepower as a 5350cc engine at 10 times the speed. that is 535 x 10,000rpm = 5350 x 1,000rpm. This applies to pretty much any engine of equivelant design.

formula 1 motor cycles are 500cc and produce several hundred horsepower at rediculously high speeds like 30,000 RPM on the other hand I have a little industrial 5HP side valve Villiers engine at home which rarely sees 3,000 and is also about 500cc.

CI engines generally rev low so the power will also be low but the maximum torque will be very low down the RPM range possibly below 1,000 RPM; which will result in powers in the 5 to 10 HP range. 2,800 might not produce much power at all however the only real solution is to either measure it or read the operation manual or a engine/vehicle data catalogue such as chiltens

You can measure the output torque of an engine using a prony brake which can be simply fabricated with a spring scale, a lever arm of specified length and a split block (with means of adjusting compression) attached to the engine output shaft.

Another form of the prony brake is shown on website http://tpub.com/content/engine/14037/css/14037_53.htm

along with the calculations for determining power output.

http://www.simetric.co.uk/si_cc2hp.htm