Injection Moulding and Tonnage

To prevent the usual kufufful that occurs when someone asks of the members of this site to calculate pizza to nth decimal places, i would suggest you define what form of tonnage you are requesting. Are you asking for output or input tonnage, what rate would you like, etc.

Assuming that you mean Tonnes(1000kg)/hour output you should consider wastage of the machine, ( in this case it would be in the flashing produced, any fin and pouring lines which do not form part of the final product, for each unit in Tonnes), you also need to consider the weight of the final product for each unit in Tonnes; finally you need to know the number of units produced per hour, this is equal to 1 divided by the cycle time to produce 1 unit in hours, you may also want to multiply this factor by an expected value of productivity, for instance if the machine can only operate for 90% of the time, then the multiplying factor would be 0.9.

Thus the Tonnage output would be

(weight of product x units per hour x productivity factor)

while the Tonnage input due to wastage would be

((weight of product + weight of wastage) x units per hour x productivity factor)

Or, could it be clamp force in tons? 2,000 PSI clamp force per square inch of cavity will do nicely.

Clamping force = projected area of product in the direction of opening and closing mould (cm2) ×the number of mold cavity×in-mold pressure (kg/cm2); Projected area of product in the direction of opening and closing mould is generated by the product appearance size. In-mold pressure is different with different materials, generally take 350-400 kg/cm2. The machine clamping force is usually greater than 1.17 times of the bulging force.