Blank Size calculation

Please elaborate the problem

You don't know how to calculate material loss in the bend?

You need to include more information.

50 + 2(25) +4(5) - 6B

where B = R(2 - π/2)

and R = radius of bend.

Depending on the accuracy you need you can do various calculations.

50 +2(25) +4(5) -6B

B=R(2-pi/2)

To make this totally accurate R = r+t/2

r= inside radius

t=material thickness.

For a quick calculation with an inside radius of 3 x t just add the inside dimensions of the component together or

L = total length of all sides - (number of bends x 2 t)

= 50 + 2 (25) + 4(5) - 6 x (2x0.9)

Blank size (A(Bending Angle)/360]x(internal Radius+KxThickness).

Or use 3D CAD for getting the blanks size.

You guys do realize this is a homework question straight out of a textbook that I used when teaching computer aided drafting & design.