Formula for Cycloidal Speed Reducer?

Any use ..?
http://www.zincland.com/hypocycloid/

Regards Woody

Thanks, Woody, I did look there, it looks like exactly what I need, but can't use it! The .pdf file is corrupted and the download is for Python, which I know nothing about.

http://www.csparks.com/watchmaking/CycloidalGears/index.jhtml

http://www.geometrie.tuwien.ac.at/stachel/Duisburg_Proc.pdf

Wally,

I was able to open the .pdf file with no problem. There are a lot of formulas and the text, except for the abstract at the beginning, is in Russian so I cannot read it. Did you look at this link on the website?

http://www.darali.com/page17.html

It seems to have some useful info.

I know nothing about Python either, good luck.

http://fluid.ippt.gov.pl/ictam04/CD_ICTAM04/SM2/10540/SM2_10540_new.pdf

or this might be easier?

http://csme-journal.nutn.edu.tw/file/02806011.pdf

Download Python and try it ..I did.

I managed to see the python files but had no useful data to input so I uninstalled it.


Regards Woody

Thanks, again, Woody. These links all refer to gear tooth forms, not pin & wheel type speed reducers, as in your first link. I tried all avenues, following all the links from that URL, but to no avail, including sending an email to jmlait, but it bounced back.

If someone could assist me with Python (is it a maths package?), that would be a great help. You see, this is terribly important, as it is for the steering gearbox on a scale model Bugatti Type 35 pedal car for my grandson!

Wally,

I build one with a chain and sprocket.That works too. You may need two teeth difference between internal and external, grinding the teeth down of the sprocket helps in clearing between the chain rollers.

What is your aim? Just confirming the principle or do you want to use it for a practical application and carry a certain torque and having a high speed input?

Hi Floram,

It is for the steering gearbox on a scale model Bugatti Type 35 pedal car for my grandson!

I also want to use the technology elsewhere, eg a turn-over fixture for large assemblies; all will be slow speed, either laser-cut or milled/routed.

I am still no further, although I have seen posts by zincboy on www.cnczone.com of the same unit, so I have registered there anf hope to contact him that way.

Hi Wally,

Google" "cyclo drive gear box" or see this link.

http://www.lifetime-reliability.com/tip_003.html

These are industrial speed reducers and are very reliable. I have bought many of those with the company I worked for.

What ratio do you need? I trust you do it for the challenge. If you simply need a reduction drive, gears are still the cheaper ones that you can usually buy.

If it is for the challenge, I do not have an answer you you without getting much deeper involved. Perhaps people on the link you provided can help? Or may be not.

The approach I would take is drawing a series of points, say every 15 degrees or less, in ACAD or SW and use the spline function to joint the dots. From there you program your CNC or laser cutting machine. It should not be too hard.

I find, even if you have mathematical formula, you still need to draw it up join the dots and feed that shape into the numerical controller. So, best to start drawing. Who cares about the math. It would only be a tool. Drawing the movement will be right for sure.

Besides the cyclo system you can also use a differential gearing with spur gears. Mind you that need at least four gears, but you can buy these.