Single Phase Load Distribution on Three Phase

No need for confussion. Do not divide by 1.73.

Because your loads are single phase loads.

You should only divide with 3

7Kw / 3 = simply 2.33 Kw.

By rounding, Your load for each phase will be 2500 watts.

take care (BB) - your power factor of 0.5 is too bad.

The power as said in #1 is 7/3 and based on the individual phases, (as if they are isolated) you can calculate the currents.

p= 3 * Vph *I ph * cos (angle)

its 7kw/3 = 2.33kw, each single phase of the three phase supply will have approxi 2.33 kw . was it helpful? reply

dear friend, yes you are correct.. thanks subhajit

Dear Signode,if all parameters given by u is correct,permit me to use cosO as cos phi.

1) In a single phase 220v(one phase),load current on the phase will be P=VIcosO, I=P/VcosO=7000/220xO.5=7000/110=63.6Amps,on the phase.

2) In a 3 phase 380v netwk(three phase),load current on each phase will be P=root3VIcosO, I=P/root3VcosO=7000/1.732x380xO.5=7000/329.08=21.3Amps

U have an advantage of reduced cable size when u distribute the load on three phase supply.U can as well use a clamp meter to test the current on single phase and the three phase load cable,u will get a value within the above range wt plus or minus tolerance.

Good luck

Patrick Whowha

Yes this is the complete reply

No Dear Friend,

Single Phase Power = Three Phse Power Divided by Three

if total Three phase power is 15 kW

Then single phase power will be 5kW

My Suggestions for you to test your self

If you have 10 number 100 wattslamps on one phase then single phase will be consuming 10 x 100 =1000 watts

same way if you have each 3 phase similar way 10 x 100 watts + 10 x 100 watts +10 x 100 watts = 30 x 100 watts = 3000 watts

Carlton Harri

Principal Lecturer

CINEC MARITME CAMPUS

Colombo

Sri Lanka

+94755958615