Previous in Forum: Trouble with Tappings   Next in Forum: Generator Problem
Close
Close
Close
2 comments
Rate Comments: Nested
Anonymous Poster

Electronic Filter Design

02/05/2010 4:54 AM

I want to design the filter for 3 phase diode rectifier.

suppose i have % ripple value for voltage and current now i have resistive load then how can i find the value of capacitor and inductor for particular value of ripple and for various configuration of filter like LC filter, PI filter , C filter....... ?

Reply
Interested in this topic? By joining CR4 you can "subscribe" to
this discussion and receive notification when new comments are added.

Good Answers:

These comments received enough positive votes to make them "good answers".
2
Guru
Engineering Fields - Electrical Engineering - Been there, done that. Engineering Fields - Control Engineering - New Member

Join Date: Dec 2008
Location: Long Island NY
Posts: 15602
Good Answers: 982
#1

Re: Filter Design - Can Anyone Help???

02/05/2010 10:25 AM

I will not attempt to teach all of the fundamentals of filter design in a blog. But you should first realize what frequency you must filter down to an acceptable ripple. My other hint is that you should remember that the voltage on a capacitor is found to be:

V=Q/C → (dV/dt)=(dQ/dt)/C → dV/dt=I/C

Now if this jogged your memory so you can safely proceed, good. If this is new to you, put down the soldering iron. You can seriously hurt yourself and others working on three phase power. If this is a homework problem, you've been given a hint here to help you still do your own homework.

__________________
"Don't disturb my circles." translation of Archimedes last words
Reply Good Answer (Score 2)
Guru
Hobbies - DIY Welding - Wannabeabettawelda

Join Date: May 2007
Location: Annapolis, Maryland
Posts: 7940
Good Answers: 458
#2

Re: Electronic Filter Design

02/08/2010 10:32 AM

GA Redfred.

Also for the inductor, remember that V=L*(di/dt). Aother handy thing to work with are the energy forms of the capacitor and inductor.

W=½CV2 for a a capacitor, W in Joules, C in Farads

W=½LI2 for an inductor, W in Joules, L in Henries

Good luck on your quest.

Reply
Reply to Forum Thread 2 comments

Good Answers:

These comments received enough positive votes to make them "good answers".

Previous in Forum: Trouble with Tappings   Next in Forum: Generator Problem

Advertisement