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3 comments
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Participant

Join Date: Mar 2010
Posts: 2

Torque Required to Run a Roller

03/18/2010 3:34 AM

Hallo,

I have a problem

i want to know why my Invertor is burn.

for Load

use F=ma = 5000*.167= 835 N
and Torque= F*r = 835 * 0.20 = 167 N.m

for Motor

Omega W=n * 2pi/60 = 2990*2*pi/60 = 313

Torque = P / W = 2600 Watt/313 = 8.31 N.m

ration of wheel = 50:1 then 8.31*50 = 415 N.m

My Motor have Torque = 415 but load only 167 N.m. Why my invertor is broken ?

or i have miss calculate

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Anonymous Poster
#1

Re: torque required to run a roller

03/18/2010 6:09 AM

have you taken care of friction et al while calculating the required power?

What about the motor starting current (typically 5-7 times FLC unless you have VFD or other starting mechanism)

When did it burn? at start or later?

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Participant

Join Date: Mar 2010
Posts: 2
#2
In reply to #1

Re: torque required to run a roller

03/18/2010 9:14 PM

I used Motor

for star-delta start

star- 230 volt 50 Hz 2.2 kW 6.2 A

delta- 400 volt 87 Hz 2.6 kW 6.2 A

but i used invertor that mean motor have alway 2.6 kW isn't it?

I think it overload while acceleration from 0 to 0.5 m/s

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Active Contributor

Join Date: Oct 2009
Posts: 10
#3
In reply to #2

Re: torque required to run a roller

04/27/2010 2:29 AM

In Star it should be 400 V 50 Hz

In Delta it Should be 240 V 50 Hz

What are U using a VFD?

In Delta are U using 87 Hz?

What is the application of this roller?

Please mention the Motor Nameplate and Inverter Specifications?

Waiting for Ur reply

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Anonymous Poster (1); dewz (1); Zalaid Khan (1)

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