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Formulae related with rotating discs.

03/20/2010 1:12 PM

1.Can anyone give me the formula required to calculate the power required by an actuator to flip a door of a given mass about a hinge, through some angle???...

Also... the formulae and considerations to be accounted while designing its hinge.

2.Formula to find the power required to rotate a disc, by 2 means:

(1)Rotating the disc with a co-axial shaft.

(2)Rotating the disc with a belt along its perimeter.

PLS HELP!

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#1

Re: Formulae related with rotating discs.

03/20/2010 4:16 PM

1) THE POWER FOR ACTUATOR IT WOULD BE : W = weight of the door m = mass of the door s = distance ...but since the door is swing when it's fliped angular distance will have to be considered ... t = time taken to complete movement W= F =mg ( g=9.810) so the formula is: P = (F*S)/t 2) ROTATING THE DISC WITH A BELT N = r/min T = torque pi = 3.14159 so the formula is: P= (2*pi*N*T)/60

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#2
In reply to #1

Re: Formulae related with rotating discs.

03/20/2010 10:50 PM

ThanQ Guest!!

Clarification:

...but since the door is swing when it's fliped angular distance will have to be considered ...

so here... instead of 'S' can i use 'R*w'?... where

R- radial distance at which actuator shaft is attached to the door,

w-angular displacement.

also in the formula the stated 'P = (F*S)/t 2)'... is the denominator t*t?

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Anonymous Poster
#3
In reply to #2

Re: Formulae related with rotating discs.

03/21/2010 2:42 AM

no sori man that formula is : P = (F*S)/t

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#4
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Re: Formulae related with rotating discs.

03/21/2010 10:36 AM

yeah got it... only then it ll be dimensionally correct.

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#5

Re: Formulae related with rotating discs.

03/22/2010 9:24 AM

This link gives the formulae for the radial and axial loads:

http://www.allegiscorp.com/docs/hingeDesignGuide.pdf

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#6

Re: Formulae related with rotating discs.

03/22/2010 1:37 PM

We could spend a long time discussing formulae but the power required to rotate a component depends on the speed at which it has to be opened i.e. its acceleration power and the power required overcome friction so that is Taccel(acceleration torque)*Theta dot= J*alpha* theta dot, where J is rotational or torsional inertia and alpha is angular acceleration and theta dot is the angular velocity during acceleration - as it varies it can either be integrated or use an average value and friction power is torque required to overcome friction multiplied by the specified speed - again use the final speed in radians per second.

The sizing of the hinge requires the knowledge of how heavy the door is, the aceleration and thus the other forces on the hinge and most important abuse it can suffer - one would make the hinge 2 to 3 times as strong as the calculated forces as people would lean on on it etc.

The power required to rotate the disc is also defined by accelerating power and frictional power and if it is belt driven there are losses in the belt drive - again use the book suggested as it explains in detail how it is done.

Look at the book called Mechanics of Machines by John Hannah and RC Stephens ISBN 0-7131-3254-X - a useful reference for these calculations.

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