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Join Date: Apr 2010
Location: Hyderabad
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Characteristic impedance calculation of a transmission line

04/26/2010 8:13 AM

A transmission line section shows an input impedance of 36 ohm and 64 ohm respectively, when short circuited and open circuited. What is the characterestic impedance of the transmission line.

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#1

Re: Characteristic impedance calculation of a transmission line

04/26/2010 8:17 AM
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#2

Re: Characteristic impedance calculation of a transmission line

04/26/2010 8:31 AM

This appears to be a homework question.

In general the CR4 community is good at helping each other. Officially we are not a homework cheat site. Unofficially there are mixed opinions, but in general homework help is only "limited" and "help". If you want someone to do your homework for you I suggest you offer a pizza to the smart looking student in the second row. If you want to do your own work and need a little help then it is important that your posting indicate that you have done work and helps us understand what part of the problem is causing the trouble.

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#3
In reply to #2

Re: Characteristic impedance calculation of a transmission line

04/26/2010 11:10 AM

This is not a home work question buddy. It is one the question asked in Engineering services examination. I know and understand the concept of surge impedance. Please help me in giving the answer rather than passing comment.

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#4

Re: Characteristic impedance calculation of a transmission line

04/26/2010 11:24 AM

Sorry for the trouble guys, Finally i googled it out. I am pasting the formula for users understanding. Short For the case of a shorted load (i.e. ZL = 0), the input impedance is purely imaginary and a periodic function of position and wavelength (frequency) Z(in) = Z(0) x tan(beta x l) Open For the case of an open load (i.e. ), the input impedance is once again imaginary and periodic Z(in) = Z(0) x cot(beta x l) Where beta refers to wave number and 'l' refers to length. Using given values, we get 36 = Z(0) x tan(beta x l) ----- (1) 64 = Z(0) x cot(beta x l) ----- (2) Multiplying (1) and (2) we get, 36 x 64 = Z(0) x Z(0) ==> Z(0) = 48 ohms

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