RL circuit

Please just spell your words completely. It must take considerable effort to dream up all those nonsensical abbreviations to confuse us all. I assume that your keyboard is fully fitted out with all the letters of the alphabet, why not use them? Then we would not get the impression that you are lazy.

ya i will,sorry

friends,in case of RL circuit,

the instantaneous voltage equation is v(sin(wt+a))=Ri(t)+Ldi(t)/dt.

i can understand the above eqn.but my problem is i cant understand the below mentioned current solution for that circuit

i(t)=Isin(wt+a-b)-Isin(a-b)e^(-t/T).

where b=tan^(-1)[wL/R]

please explain me this current equation.what the constant a really means..

Thank you very much. You will be more likely to get help if you take the time to communicate properly. You will be taken more seriously, too.

Cheers.

The constant 'a' started from the voltage equation v(sin(wt+a)) and it appears in the current equation from there (I am guessing the solution for i(t) from the differential equation is correct). If you don't have problem to understand the differential equation v(sin(wt+a))=Ri(t)+Ldi(t)/dt and its solution to for i(t), you should not have problem to understand the meaning of 'a' in the equation of i(t).

For the voltage equation, the constant 'a' determines the value of the voltage at t = 0. If a=0, the voltage is zero at t = 0, its value could be anything from 0 to π (PI).

- MS

ya friend,Im satisfied with what u explained for a.but what about current equation.

derive the answer and you'll know what is means..

i searched 4 derivation ,but no use frnd.......

dont search it is useless.. derived it by yourself... and apply some examples.. if you know how to derive.. even without the formula.. you can solve directly the circuit.. and this should be taught in your electrical engineering subjects.. it is part of the basics..

nope,could u please help me about the basics?