Calculate System Power

Please try HOMER software(free download) to get the details.

Homer software link

http://www.freedownloadscenter.com/live/HOMER-software/software.html

can i select 5KW panel system and 10KW battery system. as you know panels charges to battery till 10KW then i can supply to 10KW pump motor?

Hello, Just to be sure here: you have a 10 kW pump, need to run if for a total of 4 hours a day. The first aspect you have to see is the energy you will need every day. In this case, multiply 10kW times 4, so that is a total of 40 kWh.

As was mentioned earlier, you have to define the time at wich the system will work (mornings, afternoons, nights), and then define the ampunt of days without sun you might have in a year (this will depend on where you live, also if you have a radiation per month graph, that will help you a lot, because you can actually design based on the worst month). If you have all that, I think we can further help you out!

i will run the pumping motor 2 hours around 10am. 2 hours around 10pm.

Hello again,

Ok, where are you located exactly? do you have radiation data?

Becasue you will run the system at day, than I would say that you could dimension the batteries for two hours of load, of course, once again, it will depend where you are!

You also need to specify the type of prime mover is driving your pump? AC or DC motor? If AC, you need an inverter for AC conversion. If operation is during the day, batteries may not be needed or necessary, another cost savings?

Thanks to all of friend. I am from south of Turkey. There is lot of sunshine.

Why you must have a 10 KW irrigation system? Why you should have intermitent pumping cycle while considering solar energy? and why you must have to provide for the batteries?

Keep the pump runing whole solar day to fill a slightly elevated reservoir, batteries are not needed, you will use the stored water during any part of the day or night for irrigation.

Small scale irrigation systems of less than 2 KW are economically competitive with conventional pumping systems.

Peak flow of 1.5 to 3.5 l/s (ie, about 25 to 60 cubic meter / day) are required for irrigating 0.5 to 1.5 ha land holdings, lifting water between 2-7 m. The required peak power output (i.e. hydraulic power) range is thus 50 - 300 W.

Use a single-stage centrifugal pump directly coupled to the DC motor. Achieve a good overall performance under varrying levels of solar irradiance by matching optimum efficiency of motor-pump combination to coincide closely with that of solar array.

Select small pv modules (20Wp maximum) with open circuit voltage of about 80 v.

In Turkey I guess isolation of the range 6 kWh / sq. m on a horizontal plane is there, if the climate is humid use a figure of 5 instead.