If you have a transformer name plate which dictates:
Isecondary(rated) = 3000A
Vsecondary(rated) = 720V
Is the transformer impedance not:
Z=V/I
Z=720/(sqrt(3)) / 3000A
Z=.13 ohms?
Also, can someone explain to me how they get the following rule of thumb formula for calculating short circuit power:
Short circuit MVA = 100*S / (X%)
where S = Rated transformer MVA
X% = percentage impedance of the transformer
Thanks
The
impedance (or resistance to current flow) is important and used to
calculate the maximum short circuit current which is needed for sizing,
circuit breakers and fuses. Impedance is expressed as a percent. This
percentage represents the amount of normal rated primary voltage which
must be applied to the transformer to produce full rated load current
when the secondary winding is short circuited. The maximum short circuit
current that can be obtained from the output of the transformer is
limited by the impedance of the transformer and is determined by the
multiplying the reciprocal of the impedance timed the full load current .
Thus, if a transformer has 5% impedance, the reciprocal of .05 is 20
and maximum short circuit current is 20 times the full load current.
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