Power Consumed and Produced

If you are referring to the shaft power (11 Kw) it is called break horse power (BHP), in other words "BHP + Losses in motor" equals the electrical power measured by the electrical meters.

Brake HP, not Break. But yes.

Give him a break. He got all the letters.

Brake break given...

Losses. 11kW / 14.447 kW = about 24% in total losses. Probably 10-15% of that is in the motor conversion (copper losses, iron losses, windage, friction, stray) and the rest is probably losses in the mechancial power transmission devices, i.e. belts, journals bearings etc.

The mechanical power coming out of the shaft is 11 kW, that is the power produced. The electrical power put in is 15 kW, that is the power consumed. The power consumed is greater than that produced, please drink less vodka before calculating!!

Purist .....

Yes, but if Yuri calculated right, maybe he would not have asked the question! We would not be "blasting every tree in sight with a chain-gun trying to hit the Predator". Maybe Yuri will turn off his invisibility gismo and let us know if he understands better.......

I think your post straighted out the confusion perfectly. No over-unity was harmed by asking about what 'made no sense to him', so hopefully he will be back.

_{'chain guns'? Predator? I hate it when I miss the fun stuff!}

AHU - Definition by AcronymFinder

An <...AHU...> does not produce power.

<...el.power consumption 14.447 kW...> is probably sufficient to produce <...shaft power 11 kW...>.

A <...15 kW...>-rated motor is probably the nearest oversize for the application.