Lift Cable

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kirsty taylor Member Join Date: Dec 2010 Posts: 5	Lift Cable 12/30/2010 10:19 AM
	A designer wishes to calculate the thickness of a steel cable for suspending a passenger lift. The total length of the cable supporting the lift when full of passengers is 800 kg. The designer has decided to incorporate a safety factor of 10 into the lift cable. So the cable must be able to withstand 10 times the load it will actually be exposed to in service before it fails. The steel selected for the cable has a failure stress of 1050 MN m^-2 Using this information, what is the required diameter of the cable. Assuming that the cable is a single piece of steel, with a circular cross section. Ignore any effects of the cable weight. F= m x g F= down force on the cable. m= mass expressed in kg g = 10 ms^-2
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Anonymous Poster	#1 Re: Lift Cable 12/30/2010 10:54 AM
	kg is not a unit of length. You have not given us the load (maybe a typo, perhaps it is 800 kg?) How often do you plan to support the cable? More questions pending.
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kirsty taylor Member Join Date: Dec 2010 Posts: 5	#2 In reply to #1 Re: Lift Cable 12/30/2010 11:05 AM
	it was a typo
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nick name Guru Join Date: Mar 2007 Location: City of Light Posts: 3943 Good Answers: 183	#3 Re: Lift Cable 12/30/2010 2:03 PM
	It would be better if you try FIRST to solve the home work on your OWN and if you are not sure of obtained results to ask for corrections but after you give clear what you already have done and how you cam to the results. At CR4 you will find MANY willing HELP but NOBODY willing TO MAKE YOUR WORK ! Please consider that capitals are equivalent to shouting ! OK ? I want to add that either you did not understand the problem or the text was from the start erroneous since there are data you do not need and other which are required and not present.
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