Lift Cable Correct Loadings This Time

Okay, you've admitted this is homework. So let me ask you some questions.

1. What is the density of the steel used for the cable?

2. What is the formula for finding the mass of a cylinder, given the length, diameter and density?

3. What would be the total mass of the lift plus the cable itself?

4. What is the minimum force needed at the top of the cable to lift this mass?

Also -- can you answer these questions? If not, why not?

I missed this in my earlier read-through:

Ignore any effects of the cable weight.

It makes the problem even easier if you can ignore the weight of the cable.

This is about the weirdest gedankenexperiment I've ever seen. Who would ever use a single-strand cable?

"the cable is a single piece of steel, with a circular cross section."

That's NOT cable! It's rod stock. Anyway, we're ignoring it, except to size it?????????

I'd think you would want to get close to reality, but what do I know?

This makes no sense. Totally unrealistic, and tell the teach I said so.

Please forward your completed design to the Sugar Loaf Ski Resort in Maine as they are in dire need of a new Design.

(Pi/4)*d²*(1,050,000,000) = 800*10*10. (The first 10 is for the artificial g; the second is the safety factor.) Solve for d.

Meters are strange units for measuring cable diameters, unless maybe the Golden Gate Bridge.

We were often told to measure everything in meters as it is the standard unit, yes it made it all a whole lot more confusing but you get used to writing 2.3x10^-3 for example