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Motor Load Protection

02/02/2011 2:55 AM

Code says -> conductors shall be atleast 120% of full load; disconnecting means shall be atleast 115% of full load. For example, motor load is 100A, then conductor ampcity is 120A (atleast) and breaker rating is 115A (atleast). Does this mean that its not a problem to overkill the design? Say, 250A ratings for both conductor and breaker or even bigger? Just wondering, especially on the breaker, if theres an overload, current raises to say 200A, by this time the breaker has not tripped yet? and the motor, what, explodes? Please enlighten. thanks.

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Guru
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#1

Re: motor load protection

02/02/2011 4:01 AM

No harm in using much larger cables and breaker, just a waste of money and space. Please note that the breaker MUST be set to the rated motor current, so it trips when that current is exceeded....that is, even if you use a 250A breaker, you must set the overload trip to 100A. However, please also note that the breaker's thermal trip curve is much coarser than that of an overload relay, which is part of a motor starter, which is used to swtch on/off the motor. The breaker should not be used to do this....

You have some way to go in motor protection and control i am afraid...

Good luck.

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#2
In reply to #1

Re: motor load protection

02/02/2011 5:34 AM

thanks very much for the comment, it enlightens me a lot --> "MUST be set to the rated motor current". However, for a general application, does overdesign poses no safety issues especially for breakers that do not have setting options?

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#3
In reply to #2

Re: motor load protection

02/02/2011 5:43 AM

Motors must have starters to switch them on and off, they can have breakers or fuses for short-circuit protection only, not for overload protection. The IEC starndards recommend that the breaker/fuse and starter be coordinated so that each protection acts in its zone properly. So, if you have too large a breaker, which cannot be set at the motor's rated current, you may end up with an unprotected zone of medium-short-circuit currents which can destroy the starter and/or the motor. Not a good practice.

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Guru

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#4
In reply to #3

Re: motor load protection

02/02/2011 5:48 AM

Agreed! KVS! But, doesn't IEC recognise & permit damage to starter components under Type-1 Co-ordination?

Even though it may not be a good practice, it still is acknowledged in IEC as well as in IS. Anybody practices so is not violating the Standards.

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#5
In reply to #4

Re: motor load protection

02/02/2011 6:10 AM

Quite right.i remember that US practice required replacement of the starter after a short circuit, and that is how Type 1 came into being in IEC. However, i do believe that Type 2 is becoming more preferred nowadays even in USA. i don't know for sure.

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#6
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Re: motor load protection

02/02/2011 9:36 AM

I'm sorry, I forgot to tell you at first that I'm a novice. So now, does this tells me that overdesign/overrated breakers indeed has safety issues? How about for building wiring, does overrated breakers may also have issues? Sorry, this may sound silly but thanks though.

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#7

Re: Motor Load Protection

02/02/2011 1:54 PM

For a motor rated 100 Amp there will be starting inrush current hence selection of MCCB of less than 225 Amps is a design failure please be aware of that.

As for the motor circuit a MCCB just gives short circuit protection, thermal overload relay is there to protect the motor and the magnetic contactors.

Nobody has indulged in over design, in engineering practice 'factor of safety' is a necessary evil, for general load cable selection you have appropriately quoted: "calculated load x factor of safety = 120 Amps".

Codes do however bind that the rating of cable in general applications should not be less than the rating of MCCB; this is to protect the cable from overheating.

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#9
In reply to #7

Re: Motor Load Protection

02/02/2011 4:08 PM

I'm pretty sure that you don't have to go back through and upsize the wiring to match .say. a 225A CB.

(Also, in the NEC, wiring ampacity ≥ 125% FLA of motor.)

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Guru

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#8

Re: Motor Load Protection

02/02/2011 2:41 PM

Remember too that "overdesign" usually equals "higher cost." Your employer will not be happy if you regularly overdesign and break his budget. He will reduce his budget by eliminating YOU.

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#10

Re: Motor Load Protection

02/02/2011 10:53 PM

Those code references are to provide protection for the conductors and allow for startup. Remember most motors have a service factor of 1.15. It is usually best to provide separate motor overload protection.

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Guru

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#11

Re: Motor Load Protection

02/03/2011 8:46 PM

ianeil18,

We all started as novices. There are a number of good handbooks that explain and walk you through the code rules and exceptions. When I was beginning, I read the code section on motor control about 5 times before it began to make sense. With motors you are trying to provide two different types of protection--against short circuits and against running overloads. At the same time, the supply equipment must be able to safely handle and be unaffected by the inrush current while the motor is getting up to speed. This starting interval will be short or long, depending on the inertia of the load and the design of the motor.

The starting current requires (often) a larger setting or selection for the short-circuit and ground-fault protective CB (or fuses)--if their time delay is short, the size is larger. However, as others have said, too big a size does not provide any protection.

The starter has two parts--the contactor to turn the electricity on/off and the overload relay that provides running overload protection. With an overload, the enemy is heat, so the overload relay tries to mimic the heat produced inside the motor, and then turn the contactor off when it gets too hot. That is why a careful selection of conditions and size is important with it.

The contactor can be oversized, as can the conductors. There are no theoretical limits on these. However, oversizing the overload relay or the CB/fuse can cause you the have no protection. Starters are labeled with the acceptable size(s) of CB's or fuses--this is for protection against damage from short circuits, etc. So, read the instructions and follow their limits.

--JMM

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#12
In reply to #11

Re: Motor Load Protection

02/04/2011 10:41 AM

JMM, "too big a size does not provide any protection" --> this is what I've been wanting to find out or to hear from you guys - the experts. I was just wondering, from any codes that I've read, they only specify the minimum requirements. Not just for motor applications, even for simple building or residential applications, but now, the fact is -> "too big a size does not provide any protection". Should the codes also specify the maximum limit? But I guess nobody would indulge in over-design, surely their employer would eliminate them! What if, a novice like me would happen to have a spare which is too big a size and use it, would any inspector let it pass?

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#13
In reply to #12

Re: Motor Load Protection

02/07/2011 12:15 AM

ianeil18,

I will reply, based on the National Electrical Code, which is used extensively across the USA as well as in a number of other jurisdictions. My most recent editions are at job sites, instead of at home, so my quotes here are from the 2002 edition. I assure you, however, that the wording is virtually the same in more recent editions.

Look first at article 90, the Introduction. It says in 90(A) the purpose is the practical safeguarding ... from hazards. In 90(B) it explains that "Compliance therewith ... will result in an installation that is essentially free from hazard but not necessarily efficient, convenient, or adequate ..." Finally in 90(C) it cautions that: "This code is not intended as a design specification or an instruction manual for untrained persons."

Explanation: experience and education are essential to understanding and applying the code. "Minimum" standards may be a minimum size of circuit or wire or raceway, but also may be a maximum size. The word "minimum" is applied as a limit beyond which one should not go. It is not a lower value, nor an upper value, but a limit.

Next, look in article 430, on motors, because you refer to it. Start in 430.52 Rating or Setting for Individual Motor Circuit. Note in (B) that the device must be "...capable of carrying the starting current of the motor." and that the earlier 430.42(D) requires a time delay sufficient "...to permit the motor to start and accelerate its load." Back to 430.52(C)(1), you are told that you cannot exceed "...the values given in Table 430.52...". This is a conditional upper limit. Note the conditions: exception #1 allows going to the next higher standard size of device and exception #2 allows higher settings if the starting current is a problem. But, in 430.52(C)(2), you see another upper limit--you cannot exceed the manufacturer's maximum marked device rating.

The rules regarding motor circuit wiring are an example of an exception to the general rule that wires must be protected at their source of supply by an overcurrent protective device rated at not more than the wire's ampacity. Why can you allow a smaller wire on a larger breaker? Because the high starting current requires a fuse or breaker that can carry that, and the wire is sized comfortably larger than the running current of the motor (with running overload protection supplied via the starter). The temporary heating of the wire during the starting period is compensated for by the required 25% oversize wire. Over 100 years of experience have gone into this sort of a balance between ideal theory and practical reality. You will see it repeated many times in the code.

I hope this brief discussion shows why I describe the "minimum requirements" you refer to as limits, and not minimums. Throughout the code, you will find that these "minimum requirements" are sometimes the maximum size you can use, while in many places they are the minimum size or quantity.

--John M.

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#14

Re: Motor Load Protection

02/17/2011 6:20 AM

For motors (any form of starter) above 50HP and upto 150HP (like in your kase), as per the regulation in here is that maximum permissable starting current, I = 1.5 X Full Load Current :)

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