Calculating Power Consumption

Expand your question turn off your caps lock and think what is it you are asking. What power consumption? Electrical gas oil? No details = no help.

Re-compose you question. Use the ABC button to check your spelling. The one above with the green tick.

If it is electrical power consumption that you are looking for, call your electrical power provider, and ask them for the "peak kva" for that meter. They will only give this information to the person that is named on the account. Good luck!

Dear guest, when you contract a power electric service ,you must declare on your contract what is you instaled KVA on equipment at factory or shop place.

after that you have to control several issues , one of them is the so call (PF) " power factor" if you do not control PF ( the real meanning of this factor is how efficient you use the power used at place)

The power companies charge the service as follow:

1).- KWHR USED

2).- KWRHR USED ( REACTIVE KILOWATTS PER HOUR)!!! WATCH OUT !!WILL BE A KILLER IF YOU DO NOT HAVE HANDLE ON THIS LINE (90% IS THE GOAL ,BUT IF YOU INSTALL A CAPACITOR BANK YOU CAN BE AS CLOSE TO 99%, AND AFTER 91% THE POWER COMPANY WILL GIVE CREDIT TO YOUR INVOICE.ie.-IF YOU HAVE A 55% PF AND YOU INSTALL A CAPACITOR BANK OF 30 KVAR YOU CAN BE AT 96% PF AND YOU WILL SAVE $$$$

3).- CONTRACTED DEMAND( IF YOU CONTRACT FOR "TO SAY"50 KVA AND YOU USE 60 KVA,THE

POWER COMPANY WILL CHARGE YOU MORE THAN AGREED CONTRACT, SO DECLARE WHAT YOU REALLY INSTALL IN YOUR PLACE(KVA'S)

4).- PUBLIC LIGHTING CHARGE

5).- YOU MUST KEEP UNDER CONTROL THE (PF) POWER FACTOR

IF YOU ARE UNDER 90% PF , THE POWER COMPANY WILL CHARGE TO YOU EXTRA

DOLLARS , BECAUSE YOU DO NOT USE THE ENERGY PROPERLY.

SO , IS JUST ONLY SOME OF THE THINGS THAT YOU HAVE TO HAVE IN MIND

GOOD LUCK

JOSE

Please, try to use proper symbols and unit notation!

Corrections (and meanings):

kW = 1 kiloWatt = 1000 W, power units.

kWh = kiloWatthour

- electrical energy unit (in SI System J = Joule, do calculate how many kWh is has!?)

kVArh = {kiloVoltAmpereReactive Hour} -unit for reactive "energy",. kVA = reactive power unit {kiloVoltAmpReactive}. To fully understand you need to study magnetic and electric fields theory. For simple calculation you need to draw a right angle triangle or use Electrician's Tables.

kVA apparent power unit = Voltage * Current (e.g. 1000 V * A)

PF {power factor} = Active power (kW) / Apparent power (kVA) in many books has a math symbol of cos (phi)

my total load of buliding 400kva what is the formula of power consumption

??? Not enough data ???

Dear sir

i want total formula about for capacitor related.

where are u?

hi;

You can use the following formula for electrical power consumption:

P(W) = [ 1.732 * VL * IL * Cos(phi) ]

where:

P = Power Consumption in Watts

1.732 = Sq.Root of (3)

VL = Line Voltage (V)

IL = Line current (A) Measured

cos(phi) = PF

This formula applies to a ballanced 3 phase system. Actual 3 phase systems with multiple single phase loads are rarely balanced. Most of those posting here should at least scan a decent elementary Electric Power textbook. The modest hot-shot engineer sez: Do your homework. Learn the constraints and limits on any equation before using it.

Dear sir,

i have 250HP motor. voltage 1000v 60Hz, Cos=0.83. now i want to increase power factor atleaset 0.9. so, please give me star to end formula.

Hi,

250 HP = 250/0.746 kW = 335 kW

kVAR = Sqrt {Sqr(kVA)-Sqr(kW)} .......(1)

A) At PF = 0.83, kVA1 = 335/.83 = 404 kVA (approx)

From above Formula (1) kVAR1 = 225

B) At PF = 0.9, kVA2 = 335/.9 = 372 kVA (approx)

From above Formula (1) kVAR2 = 162

Therfore, Capacitor required to improve PF from 0.83 to 0.9 = kVAR1-kVAR2 = 63 kVAR

Error from the start! 250 hp * 746 W/hp = 186 500 W = 186.5 kW

Sorry, you are right!

Really wonder how this kind silly mistake I made!! Definitely mind absentism.

BTW, the formula remains the same.

You did this probably with American Speed of Light.

Yes, but you finally give a direction to the question and its amendments.

"DEAR SIR WE DO HAVE SHEET METAL PANAL BOARD MANUFACTURER ."

Does this imply that you are or plan to manufacture metal panel boards? If so: What size? How many per day? What gauge metal? etc. etc.

"MY QUSTION IS TO HOW WE CAN CALCULATE THE POWER CONSUMPTION.PLEASE GIVE ME THE HINT AND WHAT ARE THE PARAMETERS TO CONSIDER THE CONSUMPTION"

Need complete details of your facility capabilities and production plan. Without details it is impossible to provide a half-way intelligent answer. We do NOT have a crystal ball !

Yes.

It is Another assumption that it is DESIGN PROJECT.

In this case 1st you must have Mechanical/Technology design project > get data from manufacturer(s) of the installed equipment > their suggestions |or help from NEC examples.

Might I point out that a PANELBOARD is not an energy consuming device? it is a transmission / distribution device! The only energy "consumed" in the panelboard is the little bit of resistance losses in the busbars and switching devices installed.

+ (maybe) lights / horn /... if control diagram in ON IT

"Might I point out that a PANELBOARD is not an energy consuming device?"

A rather obvious observation, isn't it.

The OP reads: "DEAR SIR WE DO HAVE SHEET METAL PANAL BOARD MANUFACTURER ."

It appears that he is asking a rather undecipherable question regarding the power required to run a manufacturing operation to produce Panel Boards. N.E.I. as usual.

Sheesh!

Dear sir all,

I have a problem calculation electrical power consumption my work.please can you give me all solution so I can again to calculation alone.

thank

teuku