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Efficiency of Motor

04/09/2011 1:37 AM

Dear All,

i have lot of confusion about motor efficiency.kindly help me.

my question is below.

my mechanical shaft power is 85KW(Fan application). but mechanical engineer choosed 110KW motor for safety purpose.we are using VFD for this application.in this condition what about the efficiency of the motor?

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#1

Re: Efficiency of motor

04/09/2011 2:59 AM

same here

=====webdesign

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Guru
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#2
In reply to #1

Re: Efficiency of motor

04/09/2011 8:45 AM

Subtle spamming.

I for one don't need web design and no desire to visit your website.

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Guru

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#3
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Re: Efficiency of motor

04/09/2011 10:24 AM

So vote it OT--I did, but that's only one vote. (IIUC, it takes two to get it off the "casual reader's" view.)

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#4

Re: Efficiency of Motor

04/09/2011 12:08 PM

Motor losses (the invert of efficiency) can be separated into two basic categories, fixed losses and load dependent losses. The fixed losses, those associated with just making that hunk of iron and copper into a motor in the first place, don't vary with loading, and are the ones you need to concern yourself with because the load related losses will be the same either way. So as a percentage of total losses, the fixed losses appear to increase as load is decreased, but that is an increase in the percentage, not the amount, of losses. So when we say that a motor is 90% efficient at full load and 85% eff. at half load, the total amount of losses has gone down, but the fixed losses have remained the same which skews the percentage. Since the fixed losses are rarely more than 30-50% of the TOTAL losses at full load, there is that to consider in terms of cost of operation.

The thing that changes with using a VFD, is that the VFD is theoretically maintaining only the amount of power output from the motor as is necessary to operate it with the load connected. So from a losses standpoint, you are ALWAYS running the motor at full load, therefore full efficiency. It's not really true because there are other factors involved in the basic use of VFDs in motors that adds back in some new losses and those gets worse as speed gets very low. But in general, and especially with centrifugal (quadratic) loads like pumps and fans, the motor efficiency will remain relatively constant within the working speeds of the machine.

So how does that relate? In your application you have a 110kW motor on a load that requires 85kW. The VFD will lower the speed to where the motor output is only 85kW, so in essence the motor will be running at full load for that speed / flow and therefore it will be maintaining it's full load efficiency. If you did NOT have the VFD and were running a 110kW motor on an 85kW load, you would be running that motor at reduced efficiency. So in essence the VFD is "fixing" that problem. In addition, were the VFD not there, the only way to reduce the output of the fan would be to reduce the air flow by restricting it, which adds in ADDITIONAL losses not related to the motor. THAT is where the VFD is gaining overall throughput efficiency in the system.

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#5
In reply to #4

Re: Efficiency of Motor

04/09/2011 1:18 PM

Re: So how does that relate? In your application you have a 110kW motor on a load that requires 85kW. The VFD will lower the speed to where the motor output is only 85kW, so in essence the motor will be running at full load for that speed / flow and therefore it will be maintaining it's full load efficiency.

Your explanation has confused me, maybe I need to sit and think about it for a while.

I'm assuming that the load requires 85 kw at the full rated speed of the motor. If you slow the motor down, it will use less than 85 kw, and it will also do less than the intended amount of work.

If you want to do the full designed / intended amount of work, you must run the motor at its full rated speed, and there is no opportunity for the VFD to have any effect on efficiency (except for decreasing it because of power losses in the VFD itself).

Am I missing something?

(Aside: just to be clear though, I wouldn't reduce the motor from the chosen 110 kw size--mechanical load calculations are not exact, and operating conditions will change over time--things like increased friction in bearings or whatever.)

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#8
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Re: Efficiency of Motor

04/12/2011 7:14 AM

Don't get hung up about efficiency. So long as the motor and its drive are oversized, just, for the expected load, there will be no problem. 110kW motor for a max 85kW load sounds about right.

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#6

Re: Efficiency of Motor

04/09/2011 10:23 PM

If your fan draws 85KW at full speed, then the 110KW motor will probably operate slightly above full load efficiency. It is common for the maximum efficiency of induction motors to be maximum around 75% - 85% load.

If you are using a VFD to save energy at fixed full speed, then you will actually use more energy.
If the speed of the fan is reduced to reduce the airflow, then you can save energy.

I often see people using VFDs on pumps and fans operating at full speed permanently on the mistaken belief that they will save power.

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Mark
http://www.power-factor.co.nz

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#7

Re: Efficiency of Motor

04/09/2011 11:44 PM

Current Nema High Efficiency motors in this size will be over 90% efficient. Possibly as high as 96%.

A motor is rated on the shaft power, not the input power, so if your load is 85kw then the motor rated at 85 kw is sufficient, but won't tolerate long term low level overloads, so I agree with the oversized frame selection.

Be sure you have adequate cooling for the speed you are running. In the frame size you have I suspect you will have separate vent blower cooled to give you rated torque from zero to rated speed.

Most energy efficient inverter duty motors will be good for momentary 200% OL capability. The caveat is that most VFD's are sized at 100% of a nema sized motor size, so if you want to use the OL capacity be sure to select a VFD with sufficient capacity, and it may be up to 200% of the motor frame size. The VFD sizing is a game manufacturers play. "A" has a VFD rated 100kw for $x, no O/L capacity. "B" has a VFD for $y rated 100kw but has 150% O/L for 60 seconds. Be careful, there is much marketing hype.

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