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How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/13/2011 2:01 PM

How to calculate flat plate thickness of flat bottom storage tank?

Circular flat plate is supported by I-Beams or C- channels. Only deflection calculation & bending stress calculation is sufficient. How to calculate deflection & bending stress?

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#1

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/14/2011 12:19 AM

Deflection and bending stresses may be calculated using plate theory as found in "Theory of Plates and Shells" by Timoshenko and Woinowsky-Krieger or similar texts. To calculate required plate thickness, you must decide how much deflection and how much stress you are prepared to accept.

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#2
In reply to #1

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/14/2011 1:53 AM

I read in One book of strength of material that permissible deflection is = span / 325 is it true?

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#7
In reply to #2

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

01/23/2024 6:54 AM

Which <...book...> was that?

Is what <...true...>?

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#3

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/14/2011 6:04 AM

Refer Stress formulae by Rorke. I don't remember the initials. The book gives direct formulae for max. deflection and stress in plates of length 'a' and width 'b' under various types of loads. Consider as fixed ends the edges of C-section or I-beam welded to the plate. You can consider the case of uniform loading on the plate area between the supporting members as equal to the static head or pressure. If the fluid is moving or in agitation, you need to consider a factor of safety of 1.5 or so on the static load.

I have used the formulae to calculate deflection for fabricated rectangular tanks with bottom plates supported by channels, beams at fixed spans. Max. deflection allowed is 3 mm per Meter. Check for max. allowable stress for structural plate material which should not be exceeded.

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#4
In reply to #3

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/19/2011 8:19 AM

I do not have Roarke's book now. So I used the condition of simply supported beam with uniform load condition as suggested by you. I have some questions.

1) How to calculate Weight / Length?

I calculate the area of base plate (of storage tank) & full of water weight of tank & calculate the weight / area. In book it is given Uniform load /unit length.

2) I consider the C- channels of ISMC 100 distance between them is 500mm.

Which moment of inertia is to be consider -

a) Only plate (Length 500mm X thk 5) or

b) Assembly of plate & C channels.

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#5

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

06/20/2011 4:25 AM

Design of Bottom Plate :

Bottom Plate is assumed to be simply supported rectangular plate under uniform pressure ;

The bottom plate has been provided with stiffeners at a span of 666 mm X 375 mm

i.e. b1 = 0.666m & a1 = 0.375m.( a & b values will be as per your requirment)

Therefore, b1 / a1 = 0.666/ 0.375 = 1.7

Now, as per Table 6, page 118 of TPS(theory of Plates)

Mx = β' q1 a12 and (2.0)

My = β'1 q1 a12 (3.0)

where,

Mx = Bending moment about 'X-axis'

My = Bending moment about 'Y-axis'

D.1.1 q1 = (Hydrostatic Pressure + Unit weight of Plate ) in kg/cm2

= Pressure due to water column of 2000 mm + Weight of plate / Plate area

= [0.20 + 3000X2000x8x0.00000785/(300x200)] (considering 8mm thk. Plate)]

= 0.20 + 0.00628 = 0.20628kg/cm2

β' = 0.0555(interpolated from Table 6, page 118 of TPS)

β'1 = 0.0493 (interpolated from Table 6, page 118 of TPS)

Therefore, putting the values in eqns. (2.0) & (3.0), we get

Mx = 0.0555 x 0.20628 x (37.5)2 = 16.09 kg-cm and,

My = 0.0493 x 0.20628 x (37.5)2 = 14.3 kg-cm

Resultant Bending Moment, M1 = √( Mx2 + My2 )

= √( 16.09 2 + 14.32 ) = 21.52 kg-cm

Again, as per Cl. BSB-8, page BSB-6&7 of 'Elementary Strength of Material' by Birinder Singh ;

Section Modulus, Z1 = b4 x d2 = M (4.0)

6 Sd

where

b4 = 1 cm (Considering unit width of plate)

d = 't1' in cm. (i.e. thickness of plate to be obtained)

Sd = Maximum Allowable Design Stress in kg/cm2 = 153 MPa

= 153 X 10.19716/cm2

M = M1 = 21.52 kg-cm

D.1.2 Therefore, putting the values in eqn. (4.0), we get

1 x t12 = 21.52

6 153 X 10.19716

or, t1 = √[21.52x6/(1560.16)] = 0.287 cm = 2.87 mm

(without corrosion allowance)

Thus, thickness of bottom plate with corrosion allowance =t1+CA =2.87+2.0= 4.87mm

Hence, Thickness of Bottom Plate provided as 8.0 mm.

D.2 Stiffener Sizing Calculation for Bottom Plate :

Total load on bottom plate, W1 = Total weight of water filled tank = 12376.8 kg

= 0.206 kg/cm2

D.2.1 Considering, Section of stiffener as ISMC 75 with unit weight of 6.8 kg/m

[as per table II, page 6 of SP-6(Part-I)];

Now, uniform load on stiffener section, w1 = W1xa1 + unit wt. of section

= 0.206x0.375x100 +0.068 =7.793 kg/cm

Maximum length of un-stiffened section, l1 = b1 = 0.666m =66.6 cm

Therefore, Considering UDL on simply supported Beam;

Bending Moment on stiffener section, M1 = wl2/8 (as per Cl. SFBM-12, page SFBM-23

of 'Elementary Strength of Material' by Birinder Singh)

= w1xl12/8 =7.793X66.62/8=4320.78 kg-cm

Now, Allowable Bending Stress, σbc = 152 MPa (Refer Sl. No. C.1)

= 152 x 10.19716 kg/cm2

Required section modulus, Z1 = M1/ σbc = 4320.78 = 2.787 cm3

152x10.19716

D.2.2 But, Section modulus of ISMC 75 = 20.27cm3 [as per table II, page 7

of SP-6(Part-I)]

> 2.787 cm3 and thus satisfactory.

Hence, Actual Stiffener Size selected as ISMC 75.

D.3 Deflection calculation of bottom plate :

W1max = α q a4 = α q a4 (as per Eqn. No. 141, Page No. 117 of TPS) (5)

D EI

Where,

W1max = Maximum deflection of plate in cm

q = Uniformly distributed load, kg/cm2 /cm width of plate = q1 = 0.20628 kg/cm

a = Smaller Side of the unstiffened area in cm = a1 = 0.375 m = 37.5 cm

D = Flexural rigidity of the plate = EI [as per Eqn. 4, page 5 of TPS]

α = Numerical factor depending upon ratio b/a

E = Young's modulus in kg/cm2 = 2x106 kg/cm2

I = Moment of inertia in cm4 = (1/12)xbd3 [as per Cl. MOI-5, page MOI-4 of

'Elementary Strength of Material' by Birinder Singh]

= (1/12) x 1 x 0.83 cm4 [Considering plate width,b = 1 cm & plate

depth,d = 0.8 cm]

Now,

a = a1 = 0.375 m = 37.5 cm; b = b1 = 0.666m = 66.6 cm

For b/a = 66.6/37.5 = 2, α = 0.00486 [as per Table 8, page 120 of TPS]

D.3.1 Therefore, putting the values in eqn. (10.0), we get

W1max = 0.00486 x 0.20628x (37.5)4 = 0.00061cm = 0.0061mm

2 x 106 x (1/12) x 37.5 x 0.83

D.3.2 Now, As per Cl. 3.13.1.2 of IS-800;

Limiting vertical deflection, δ1 = a1/325 = 37.5/325 = 0.1154 cm. = 1.154 mm

Since, W1max is less than δ1 , the 8.0mm thk. bottom plate is safe under deflection.

reply me if u have any doubts

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#6
In reply to #5

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

08/06/2012 10:13 PM

Can you please guide me,

How to calculate thickness of circular end plate under hydrostatic pressure?

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Guru
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#8

Re: How to Calculate Flat Plate Thickness of Flat Bottom Storage Tank?

01/23/2024 6:58 AM
  • Instead of starting from "square 1", how about cloning a previous design and reviewing its calculations?
  • Is there a Mentor available locally?
  • How many tank fabricators have been approached for advice? Telephone?
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