Previous in Forum: In Search of Lab Equipment   Next in Forum: Lethal Substance (LPG)
Close
Close
Close
8 comments
Rate Comments: Nested
Member

Join Date: Dec 2008
Location: mexico city
Posts: 9

Kinetic Theory Of Gases

08/14/2011 2:17 AM

I had this doubt since I was in college:

My deduction for the speed of molecules in a gas does not agree with the popular kinetic theory of gases.

It goes like this:

Take a certain amount of gas molecules all at absolute zero temperature.

Now accelerate them at say one thousand feet per second and let them enter into an empty vessel.

Soon as they all entered, close the vessel. The molecules collide against the walls and start random collitions.

Now translate the original kinetic energy and transform it into heat energy and solve for temperature.

The average molecule speeds should remain constant, that is 1000 fpm, so for that speed you now know the temperature and viceversa

1/2mv2=mc(t1-t2) but since the initial temperature was zero the we have

1/2mv2=mct

so the average molecular speed of a gas should be

v=sq rt of 2ct

where am I wrong?

Register to Reply
Pathfinder Tags: kinetic theory of gases
Interested in this topic? By joining CR4 you can "subscribe" to
this discussion and receive notification when new comments are added.

"Almost" Good Answers:

Check out these comments that don't yet have enough votes to be "official" good answers and, if you agree with them, vote them!
Guru

Join Date: Apr 2010
Location: About 4000 miles from the center of the earth (+/-100 mi)
Posts: 9910
Good Answers: 1141
#1

Re: Kinetic Theory Of Gases

08/15/2011 6:37 AM

The average molecule speeds should remain constant, that is 1000 fpm

Take two molecules, one at 0 fpm and one at 2000 fpm. Average speed is 1000 fpm. Total kinetic energy KE = .5*m*(2000)^2=2000000*m. In second case, both molecules speed = 1000 fpm: KE=.5*m*2*(1000)^2=1000000*m. Conservation of Energy means that average speed is not constant.

Register to Reply Score 1 for Good Answer
Power-User

Join Date: Sep 2010
Location: South of Spain Andalucia
Posts: 114
#2

Re: Kinetic Theory Of Gases

08/15/2011 9:08 AM

It is a pity that many times silly questions get a lot of answers and help.

Your question is very interesting. and got only one.

Your reasonig must be wrong because the velocity of molecules have, since Boltzman, been measured by MANY diferent means, but it is a good reasoning.

So. Where is he trick?.

1º Can you create a flow of molecules ALL at the same velocity?.

2º If you can, starting from very low temperatures, you need a pefect thermal insulation to avoid the molecules getting energy from outside and have the Maxwel-Boltzman distribution.

3º It seems clear that if all the particles in the container have the same velocity at the begining they will keep it for ever, because the collisions are perfectly elastic.

4º The problem is that your GAS is a very unnatural gas, that may be impossible to create

5º- But may be you can, and then you got something important

Buenas tardes desde Andalucia

chorete

Register to Reply
Guru

Join Date: Feb 2011
Posts: 1119
Good Answers: 11
#3

Re: Kinetic Theory Of Gases

08/15/2011 9:32 AM

Your conservation equation 1/2mv2=mc(t2-t1) only holds true, if and only if all gas molecules comes to stop at collision. However the real scenario is, gas molecules dont stop after collision yet some of its momentum was converted to heat. The most proper way of having a conservation equation is Delta KE= Delta Q or the change of kinetic energy of gases after collision corresponds a change of temperature of the gas.

__________________
" To infinity and beyond" - Buzz Lightyear
Register to Reply
Guru
Popular Science - Cosmology - Let's keep knowledge expanding Engineering Fields - Retired Engineers / Mentors - Hobbies - HAM Radio - New Member

Join Date: Dec 2006
Location: North America, Earth
Posts: 4528
Good Answers: 106
#6
In reply to #3

Re: Kinetic Theory Of Gases

08/15/2011 6:59 PM

However the real scenario is, gas molecules dont stop after collision yet some of its momentum was converted to heat.
Heat is the movement of molecules. Are you trying to say that the molecules get hot from their collisions? I don't think so.

__________________
“I would rather have questions that can't be answered than answers that can't be questioned.” - Richard Feynman
Register to Reply
Guru

Join Date: Feb 2011
Posts: 1119
Good Answers: 11
#7
In reply to #6

Re: Kinetic Theory Of Gases

08/16/2011 1:04 AM

Yap, there's two way to view this scenario. Either you are appling heat to the gas or generating heat by the gas.

Applying heat to the gas, gets every molecule excited until such time average velocity is attained all through, every molecule might not have the same velovity but as awhole or average they could sum up into one lump quantity.

However, the other is, try to compress a gas. You realize heat is being released by the compression. Instantaneously gas molecules are disturbed and molecular velocity changed to a higher level as they bump one another more frequently at the instant as spaces in between decreases, and if the whole system is adiabatic, the same velocity of the molecules of as whole will be retain. Should it be let cool, gas molecules will again find its equilibruim state in which velocity again will decrease in accordance to equilbrium state.

Therefore, suming it up ΔKE of gas molecules = mc ΔT of the gas, that should be it.

__________________
" To infinity and beyond" - Buzz Lightyear
Register to Reply
Member

Join Date: Dec 2008
Location: mexico city
Posts: 9
#4

Re: Kinetic Theory Of Gases

08/15/2011 11:26 AM

Once the molecules get to the vessel's wall they start bouncing in all directions and start colliding against one another in different angles so some molecules increase and others decrease their speeds, but the total average should remain the same.

Of course there is no such a gas but you could take a piece of ice at absolute zero and if given a high speed it will convert into steam after the collition so in the begining all its molecules have the same speed

All this of course is mere theory and considers no friction and perfectly elastic collitions and the vessel should not absorb any heat, buta again these are perfect conditions

Register to Reply
Guru

Join Date: Apr 2010
Location: About 4000 miles from the center of the earth (+/-100 mi)
Posts: 9910
Good Answers: 1141
#5

Re: Kinetic Theory Of Gases

08/15/2011 12:40 PM

"The average molecule speeds should remain constant"

Here's another example: Molecule A is stationary and molecule B travelling at 5, strikes it and the two separate at 90 degree angle (ask any pool player) such that A now has velocity 3, B has velocity 4. Total energy is conserved (25*m/2). Momentum is conserved (cg moves 2.5 units/sec in same direction as original B). Average speed before collision = 2.5. Average speed after collision = 3.5

Register to Reply
Power-User

Join Date: Aug 2010
Posts: 209
Good Answers: 8
#8

Re: Kinetic Theory Of Gases

08/16/2011 5:54 AM

The short, quick and correct answer to where you are wrong is that you are ignoring the effect of collisions with the walls of the container. The collisions with the walls take place with conservation of energy and momentum. According to your scenario, there are no other gas molecules in the container, so there are no interactions with other gases. The temperature of the vessel gives the vibrational energy of the molecules of the wall, with which the gas molecules equilibrate. You have not stated what is the composition of the gas, that is, whether the gas is made up of a single type of molecule or is a mixture, or whether it has a polyatomic structure allowing internal movement which can partition some energy. Then of course there is the issue that real gasses do not obey the Ideal Gas Law, but have deviations from it.

I recommend that you study the physical chemistry of gasses further. From an engineering viewpoint, the theory of gasses is correct as traditionally stated. The additional deviations arising from quantum considerations and general relativity will not affect the measurable speeds unless you actually have a lab which generates very low or high temperature.

I would also suggest that you learn how to use superscripts and subscripts in writing your equations on this site. It should make comparisons with texts, etc., easier for all of us.

Register to Reply
Register to Reply 8 comments

"Almost" Good Answers:

Check out these comments that don't yet have enough votes to be "official" good answers and, if you agree with them, vote them!
Copy to Clipboard

Users who posted comments:

Chorete (1); inedesca (1); Noudge79 (2); Rixter (2); StandardsGuy (1); woodpower (1)

Previous in Forum: In Search of Lab Equipment   Next in Forum: Lethal Substance (LPG)

Advertisement