It will decrease because Power=(2*pi*Speed*Torque)/60.....
Another doubt is, As induction motor specified at 1500 R.P.M, if we run at 500 R.p.m what is speed torque characteristics..? will it be same proportional as standard or Will it vary at low speeds...?
(1) The Voltage is proportional to Frequency (maintains constant V/F ratio) up to the rated frequency (or rated voltage)
(2) Torque is constant up to the rated frequency and then decreases
(3) Power increases up to the rated frequency and then constant
(4) Motor rated power and rated speed are obtained at rated voltage
(5) And off course, the motor speed is proportional to motor frequency.
Up to the rated frequency, the torque is constant. From the speed-torque-power equation (HP = Torque x Speed/5250), the motor output power is proportional to the speed or frequency or voltage up to the rated voltage.
For your case, you may expect (32 x 500) / 1500 = 11 KW (approximately) output from the motor at 500 RPM.
- MS
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