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Incremental Encoder

09/24/2011 7:33 AM

We have a Incremental type Encoder giving output 1024 PPR.

I have some doubt regarding this

1. in first cycle it gives 1024 pulse,then in second cycle is it 1024x2? & so on

2. if above is true then how the no of pulses increase in second revolution?

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#1

Re: Incremental Encoder

09/24/2011 8:54 AM

During the first revolution (360°) it will produce 1024 pulses. During the second rev. it will produce 1024 more pulses. Total pulses for 2 revs = 2x1024 = 2048.

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Guru
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#2

Re: Incremental Encoder

09/24/2011 9:36 AM

Every incremental encoder I've worked with have three pulse outputs; A, B, and Z or I. Many have the compliment signals allowing for a differential (RS422) transmission due to the potentially very high speed of these pulses and a need to then to apply transmission line cabling terminations. If you don't properly terminate and wire these signals you can easily get cabling signal reflections that will generate erroneous pulses. This is particularly true for the Z or I signal for it exists only once per revolution. If there are 1024 pulses for A and B individually then Z will be TRUE for 1/4096 of a revolution.

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Anonymous Poster #1
#3

Re: Incremental Encoder

09/24/2011 2:00 PM

It's a concept called addition. You add the next rev pulses to the last sum, and so on. S.M.

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#4

Re: Incremental Encoder

09/25/2011 2:37 AM

Simply, the encoder will give you 1024 Pulses Per Revolution, and that is constant so in each revolution will be 1024 pulses only, then it's up to an external controller that will count/add/multiply/devide...etc .

so for your question #2 : the number of pulses doesn't increase .

example: if the encoder turns 5 revolutions then

the total number of pulses =1024+1024+1024+1024+1024=1024x5=5120

i hope this was clear.

Amer

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