Wire Rope Sag Calculations

It's sag, not slag.

Sag & Tension Calculation

careful who you call a 'sag' !

Amount of sag is directly related to amount of tension on the rope, and will be the shape of a parabola. You gave us little to no meaningful information to go on here...

• What amount of sag is considered "OK" for this installation?
• size of the rope has little to do with the poles failing, other than the weight of the rope.
• The whole key to your puzzle is how much Tension is on the rope?? This relates to my first point about sag, and how they are related.

At some point when you get enough tension on your rope, it will impart a certain amount of Stress to the poles. It is impossible to say if the poles will fail or not considering we have no clue how the poles are fixed to the ground, as this will typically be your weakest point.
So start here:
How much sag is allowable? No sag? Sag down to the ground? somewhere in-between?
Otherwise it's a wheel spinning competition, and no one is getting anywhere.

Guys, Thanks for correcting my spelling. By the way I am look at 2 - 3 ft sag to be ok. Because anything more than that would interfere with other systems. For this calculation purposes I consider the poles to be perfectly rigid. But, on a second thought, I would like see if there is a way to figure out if the poles fail and if it's better to use larger diameter poles. Lyn, I tried to open that link, it didn't open to anything. I suspect if this could be my OS5 Thanks C1

and will be the shape of a parabola.

Not so. A cable with no suspension members - only supporting it's own weight, - forms a catenary:

http://en.wikipedia.org/wiki/Catenary

http://teachers.sduhsd.net/abrown/Activities/Matching/answers/catenary.htm

Everything else looks good.

OK... OK.... I'm technically incorrect... but... "superficially similar in appearance to a parabola".

I guess I should have added "Roughly" the shape of a parabola.