Problem 7-4 Loss of heat sink in a sodium-cooled reactor (section II)A
1000 MW(t) sodium-cooled fast reactor has three identical coolant loops.
The reactor vessel is tilled with sodium to a prescribed level, with
the remainder of the vessel being occupied by an inert cover gas, as
shown in Figure 7-26 . Under the steady operating condition, the ratio
of the volume of cover gas to that of sodium in the primary system is 0.
1. At time t = 0, the primary system of this reactor suffers a complete
loss of heat sink accident, and the reactor power instantly drops to 2%
of full power. Using a lumped parameter approach, calculate the
pressure of the primary system at time t = 60 seconds. At this time,
check if the sodium is boiling.Useful dataInitial average primary system
temperature = 980°FInitial primary system pressure = 50 psiTotal
primary system coolant mass = 18,000 Ibmβ (volumetric coefficient of
thermal expansion of sodium)= 1 .6( 10 ^- 4) ; oFcp for
sodium = 0.3 BTU/Ibm OF (at 980°F)ρ for sodium = 51.4 lbm/ft) (at
980°F)Sodium saturated vapor pressure:p = exp [18.832 - (13113/ T) -
1.0948 ln T + 1.9777 (10^(-4)) T]where p is in atmospheres and T is in OK.
Answer: p = 87.9 psiT = 1190.7°F, so no boiling occurs
can anybody solve this question this is taken from chapter-7 of Nuclear system I- Thermal Hydraulics Fundamentals
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