Re: The Tonnes of Steel

~490 lb/ft³

Vino,

490 x 3 ft will yield approximately 134,000 tonnes per 66,000 x 3 = 402,000 thousand tons or is my calculation incorrect?

Elvis

What is your interest in this?

I'll make a bid on the steel. Are you the right agent to deal with?

My Dear Friend,

we might just be in luck...I am making the determination of how much steel so that I could in fact make logistical arrangements for shipment at the appropriate time.

Yes, I am the Owner of ths steel. If you are interested yes, by all means I would like to talk with you immediately so that we could reach an amicable arrangements...when are you able to travel and see the steel?

CR4 Admin: phone number removed

CR4 User,

I live in Freeport, Bahamas 56 miles from West Palm Beach....

I am headed to bed however, if you woudl like to discuss further and immediately, please contact me

Would still like to have greater calculations to tonnes.

I await your response,

Elvis

CR4 Admin: phone number and email address removed

What calculation?

Steel weighs approximately 490 pounds per cubic foot, depending on alloys.

We need to find total cubic feet of steel in Tank, Pipeline, and Sumps.

Cubic Feet in Floor plus Roof = Thickness * ∏ * Tank Radius 2

Tank floor = 4/8", Tank Roof = 5/8" + 5/8" = 14/8 = 1.75 inches = 0.146 feet

Floor+Roof Cu Ft = .146 * 3.1416*145*145 = 804 cubic feet = 393,960 pounds steel in roof and floor

Volume of Cylinder = Area Base * Height of Cylinder

Area of Base = ∏ * Tank Radius 2 = 3.1416*145*145 = 66,052 sq ft

Tank Wall Height = Volume of Cylinder / Area of Base

1 bbl = 5.6146 cu ft

750,000 bbl = 4,210,937.500 cu ft

4,210,937.500 / 66,052 = 63.75 feet cylinder height (note this does not include extra height above floating roof)

Tank Wall Area = Circumference * Height = ∏ * Tank Diameter * 63.75

Tank Wall Volume = Area x Thickness = 3.1416 * 290 * 63.75 * (Unknown Wall Thickness) = Can't be solved from information provided.

Using estimate for wall thickness of 1 inch (presumes internal tank wall reinforcements) = 4840 cubic feet of steel = 2,371,613.475 pounds of steel

Tank Steel Weight = 2,765,560 pounds steel

Pipeline Steel Weight can be found considering the pipeline to be a cylinder.

Using same equation as tank wall we find

3.1416*3feet*200feet*.052=98 cubic feet = 48,029 pounds

Weight of Sumps - not enough information to calculate

Weight of Pontoons - not enough information to calculate.

Estimated minimum weight based on information available = 2,813,589 pounds or 1,279 metric tonnes.

I used 42 gallons per barrel and 12 inches per foot to make these calculations.

Check my math, I did this on my abacus and I am tired

TxMedic good morning,

just reading and trying to understand fullly the equation I too am tired,

The equation is incredible and thank you so, so very much. I will let you know how it works out perhaps I owe yo lunch someday....lol

Again, many thanks and all the best.

Get some rest.

Elvis

Hi Elvis,

I caught some mistakes in my math -

Volume of Steel in Roof(R) and Floor(F) = thickness * area of R*F

V=1.75inches * 1foot/12inches * 3.1416(pi) * 145feet(radius) *145feet(radius)

V= 9643.6124 cubic feet in floor and roof = 4,725,370.0956 pounds in R+F

Continuing with the correction, to calculate the volume of steel in the wall of the tank, we need to know the height of the cylinder. I calculated how big a cylinder I would need to hold 750,000 barrels.

1 bbl = 5.6146 cu ft

750,000 bbl = 4,210,937.500 cu ft

Volume of Cylinder = Area Base * Height of Cylinder

Area of Base = ∏ * Tank Radius 2 = 3.1416*145*145 = 66,052 sq ft

Tank Wall Height = Volume of Cylinder / Area of Base

4,210,937.500 / 66,052 = 63.75 feet cylinder height (note this does not include extra height above floating roof which may be as much as another 10 feet?)

Now we have an approximation of the tank wall height. Next we need the area of the wall which is the height times the width (circumference). The circumference of the tank is approximated by pi * diameter = 3.1416*290 = 910 feet.

The Total Wall Area (TWA) is the length of the wall (910) * the height (63.75) =58012.5 square feet

Tank Wall Volume (TWV) is the thickness of the wall * the area of the wall. Since we don't have the thickness, I guessed 1 inch to make the math easier.

Tank Wall Volume = Area x Thickness = 58,012.05 sq ft * 1 inch * 1ft/12inches = 4,833 cubic feet

TWV=4,833 cu ft, so there are 4,833cu ft * 490pounds/cu ft = 2,369,150 pounds of steel the tank wall if the 1" thick wall estimate is correct and the height estimate is correct.

So, we can say that you have approximately 7 million pounds of steel in the tank if the wall thickness is correct and the height estimate is close to correct.

There's some weight to the pipeline and the sumps... perhaps those numbers are insignificant compared to the tank weight. You did not mention the pontoon structure so there's going to be some weight there also.

Sorry about the earlier mistakes. My new rule is not to post until I check my math after a nap!

Where is the tank? When do you have to have it dismantled and removed?

TXMedic,

thank you very much for correction in your math thetank height is 66' x 290' based on your calculations of yesterday and taking in consideration the sumps, internal pipes, water drains, roof legs (149), other piping 4' to 6' internal and the 36" line into tank (well in excess of 200 ft") I estimate 500,000 tonnes in R + F+ pipes etc.

The steel is located in Freeport, Bahamas.

Your calculations has made it easier for me to prepare a bid package knowing that persons interested will get a concise approximation....if there is sucha a thing.

Best regards,

Elvis

Elvis,

7 million pounds is 3,200 tonnes.

your 500,000 tonnes estimate would be 156 times more weight.

How thick are the tank walls?

Before you put in a bid, may I politely suggest that you determine how much crane rentals, gas for cutting torches, cutting torches, trucking to port etc will cost? Not to mention labor.Milo