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Power-User

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Magnet Question

10/18/2012 10:42 PM

Hello all HOPE all is well. I have a question about magnets. Does two repelling magnets on a rotor either s/s or n/n passing a coil thats in between them induce a current? if so would it be equal to less than or greater than the current a set, of n/s magnets would do in the same situation?

thank you for any help in advance

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Guru

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#1

Re: magnet question

10/18/2012 11:34 PM

Yes; less

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Power-User

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#6
In reply to #1

Re: magnet question

10/19/2012 1:53 AM

How so and by how much please? I mean like half the current is it more like an Eddie current ? thank you for your reply.

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#7
In reply to #6

Re: magnet question

10/19/2012 2:02 AM

Maybe a Fast Eddie Felson current....

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Power-User

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#10
In reply to #1

Re: magnet question

10/19/2012 5:49 PM

What is that ? I ask A question as to whether current is induced when two opposing magnets pass a coil. Like i said pondering if the gauss factor is the same the field lines strength the same magnets identical. The magnetic field cuts the coil as it passes it so were is the difference is it related to direction of the field lines ? Also I don't see were perpetual comes in to this question. NOW it seems the word perpetual gets said by administrator and the whole discussion is plagued.

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#2

Re: magnet question

10/18/2012 11:46 PM

Does two repelling magnets on a rotor either s/s or n/n passing a coil thats in between them induce a current?

I don't think so. For an electric current to be induced, their must be motion that interrupts a magnetic field between two unlike poles. Like poles have diverging magnetic fields. For this reason, no motional emf can be induced.

Also, aren't the magnets in this set up electromagnetic? i.e their magnetism and polarity switch for each period of revolution...wait...I am thinking of an ac generator with slip rings.

The same is may or may not be true for a brushless dc generator.

Your question has the perfect recipe for an experiment

Brushless dc generator

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#3
In reply to #2

Re: magnet question

10/19/2012 12:31 AM

Huh? Your three pix all have brushes.

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Power-User

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#9
In reply to #2

Re: magnet question

10/19/2012 2:19 AM

Please fill us in on the results.

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Guru

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#4

Re: magnet question

10/19/2012 12:45 AM

You're trying to make a perpetual motion machine, aren't you ?

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Power-User

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#5
In reply to #4

Re: magnet question

10/19/2012 1:49 AM

Really just trying to learn, pondering if its just field lines and Gauss factor how does the copper not get cut, the field lines would be of same strength unless its a pole directional thing ?

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#8
In reply to #5

Re: magnet question

10/19/2012 2:10 AM

A lot of car makers believing that pulling a car is much easier then pushing a car all things being relative.IT should take the same amount of energy either way from a rest position. Personally I prefer the push position at least if it gets away from me I wont be ran over.

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#11

Re: Magnet Question

10/20/2012 1:42 AM

The answer would be more obvious if you would use "real" graphics. The image of the fixed south only magnetic field with the brush-connected rotating coil shows no north (N). If you know how to build that, let us know also. A normal design might have a rotating magnet and a continuously connected coil in which the lines of magnetic force have to be connected S to N. this would make the necessity of the presence of both N and S more obvious. The answer "Yes, but less current" (GA) would be more clear if you actually drew the "real" field

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#12

Re: Magnet Question

10/20/2012 8:01 AM

How can something be between and passing at the same time. Now at some point in time it maybe between them as it's passing. The fact that it's passing and the flux fields are crossing the coil creates the current.

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Guru

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#13

Re: Magnet Question

10/20/2012 2:08 PM

The question is really why you should bother to ask the question. You postulate a S/S or N/N on the rotor, where presumably you mean the stator. Your rotor coil hopefully is correctly wound. When the coil is moved past one N pole, a current is induced in one direction, but since the other end of the coil is moved past another N pole, the current induced will be in the opposite direction, and no current at all will flow. Perhaps you are postulating that the coil could also be wound in a contrary fashion. This would in effect mean two separate coils with a total of 4 connectors at the commutator. slip rings. This could work, but the magnetic field is going to show such a poor gradient that the current output is going to be poor anyway. The question is, as I say, why bother?

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Power-User

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#14
In reply to #13

Re: Magnet Question

10/20/2012 6:52 PM

Just asking a question, So far the range of answers are yes lower, no they cancel out,and an engineer friend of mine local believes they would make higher current. I am not postulating just curios. I ll have to set it up and tell the results.

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Guru

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#15
In reply to #14

Re: Magnet Question

10/21/2012 9:53 AM

If that is the case, then keep him as a friend, but under no circumstances get him to do any engineering for you. The laws of physics must be obeyed.

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Guru

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#16

Re: Magnet Question

10/21/2012 6:21 PM

If the poles have equal magnetic flux and the coil is passed through equidistant between then there will no induced current.(The flux at that point is zero)

From the illustration in '2' if the axle of the rotor was set centrally between the poles, I think the EMF induced in one side would be cancelled by the emf induced in the other side, result = 0 current.

With the axle offset as illustrated, there would be a 'very small' chaotic alternating current simply due to the asymmetry - ie each coil end/side passes each pole while the other is distant from either pole, and the flux near the pole is curving away from it - ie 1. it is not a smooth field and 2. it is continually changing direction

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Participant

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#17
In reply to #16

Re: Magnet Question

10/26/2012 6:28 AM

I agree with you answer.But to help Johnny b5 he has to consider the coil as a complete circuit and with the ,say, North pole going past coil on one side it will induce a current to flow , say, Upwards and at the same time the other North pole is inducing a current to also flow Upwards on opposite sides of the same coil. The two currents will cancel each other out resulting in no current flow.

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#18
In reply to #16

Re: Magnet Question

10/30/2012 10:48 AM

<there would be a 'very small' chaotic alternating current simply due to the asymmetry>

GA

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