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Anonymous Poster

Shear Modulus and Max Shear Stress

09/15/2005 2:36 PM

Mike Messenger writes:
Sorry this is a little boring but I'm tired of reading texts that don't answer this question.

Most material property data sheets include the Elastic Modulus (E), Shear Modulus (G), Yield Stress (tension), and max tensile stress. If I am loading a pc so steel strictly in shear, how can I determine the max load before failure. CR1020 steel is an isotropic material for example, does this mean I can assume the max shear stress is the same as the max tensile stress? I've seen examples in texts where the shear strain is calculated using the Shear Modulus and actual shear stress. But what about the failure load?

Please advise....someone!!!

Thanks,
Mike
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Pathfinder Tags: elastic modulus material property max tensile stress shear modulus yield stress
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cmac
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Join Date: Apr 2005
Posts: 21
#1

Mises

09/15/2005 10:45 PM

You need to look up the formula for the Mises Stress. The Mises Stress is a combination of normal and shear stresses in all directions -- it takes the entire stress state into account -- and a material will yield when the Mises Stress is equal to the yield stress for that material.

If a material is under uni-axial normal stress, the Mises formula reduces to that stress only. In uni-axial shear, the formula comes down to something like sqrt(3) times the yield stress.

Does that make sense? I can dig up the formula if you can't find it, but there are all kinds of squares and square roots so it's not fun to type.

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