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Join Date: May 2007
Location: Australia
Posts: 27

Velocity head in part-full pipe

07/06/2007 12:25 AM

Hi ,

could anybody shed more light on finding the Velocity head of water flow in a partially full pipe? Except the Usual chart relating Y/D ratio to V/Vf , Q/Qf and so on.

Thanks

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Anonymous Poster
#1

Re: Velocity head in part-full pipe

07/07/2007 1:04 AM

V^2/2g, in traditional units.

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Guru
Engineering Fields - Environmental Engineering - New Member APIX Pilot Plant Design Project - Member - New Member

Join Date: May 2007
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#2

Re: Velocity head in part-full pipe

07/08/2007 8:52 PM

Divide volumetric flow rate by cross-sectional area of pipe filled with water to obtain your water velocity v, then apply formula h = (v^2)/2g.

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Associate

Join Date: Feb 2007
Location: Concord CA, (near San Francisco)
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#3

Re: Velocity head in part-full pipe

07/09/2007 8:08 PM

Hamid:

It's a little more complicated than posters nos 1 and 2 indicate. You need to apply something called Hydraulic Radius to get the equivalent flow area. It would be too long to explain it here, but if you can get Crane Tech Paer 410, it gives a good explanation and formulas you can use to calculate what you need. Try Google, as well, or an engineering website you may know for more. Good Luck

Hank

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Associate

Join Date: May 2007
Location: Australia
Posts: 27
#4
In reply to #3

Re: Velocity head in part-full pipe

07/09/2007 9:05 PM

Hi Hankt,

Thank you for your help. I did search the google and came up with the outcome which posted in discussion on July 9 issue.

Thank you again for your concern.

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Users who posted comments:

Anonymous Poster (1); DVader1000 (1); Hamid K Saberi (1); Hankt (1)

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