Mutual Resistance Between Two Feet

You'll need to calculate the run factor to determine the mutual resistance between two feet.

Try Google. "mutual resistance between two feet".

Do your own homework.

There's nothing like empirical evidence.

Try clipping the leads of a DVM on opposite toes and jumping up and down.

...and do put it on YouTube so we can all have a laugh.

What is it with electric current into people lately. Is there a sudden desire for easier methods of torture?

The 18-certificate film entitled "50 shades of grey" has just been released in the UK. You can interpolate the rest yourself.

In my opinion the "mutual resistance" it is a virtual value what has to be subtracted from foot resistance in order to fit the calculated feet-earth resistance with measured one.

According to IEEE 80/1986-in the new IEEE 80/2000 it is not shown more-the resistance for hand-to-hand is RA=RB+2(Rf-Rmf) and Foot-to-foot RA=RB+0.5(Rf+Rmf)

RB=Body resistance [1000 ohm]; Rf=ro^(4*b) =foot resistance; ro=earth resistivity b=equivalent radius of a foot[m]; Rmf= feet mutual resistance.

As in Schwarz equations a mutual resistance between grounding rod bed and grid resistance has to be inserted in order to fit the measurements. See IEEE 80/2000 ch.14.3 Schwarz equations.

See [for instance]: http://www.emo.org.tr/ekler/3fce7f4788a4b8a_ek.pdf

Also a good reference it could be:

Practical Grounding, Bonding, Shielding and Surge Protection by Mark G. Vijayaraghavan

In my copy of a draft British Standard of 2005, the human body is modelled as a set of internal partial impedances plus skin impedances. The internal impedances are largely resistive and the skin impedances capacitive. Unfortunately all the tables of values of total body impedance relate to hand-to-hand current, but adding up the partial impedances of each body part suggests that the foot-to-foot impedance is much the same as the hand-to-hand impedance, i.e. around 1000 ohms. An important difference between the paths is the heart current factor, which represents the relative risk of ventricular fibrillation: if the factor for the left hand to both feet path is 1, then the factor for left hand to right hand is 0.4 and for left foot to right foot it is only 0.04.

This is relevant to the death by iPhone thread. There would have been virtually no risk in a current path from charger to hand and back to charger, but a certainty with current from hand to the rest of the body, bathwater and earthed plumbing.

Reading between the lines here I think sensourabh may be referring to "step potential". In the vicinity of an uncleared earth fault the potential of the ground is raised above earth potential. This potential decreases as the distance from the fault at a ratio dependent upon the conductivity of the earth material. Anyone walking in the area will experience a difference of potential between his left foot and right foot. This is why personnel shuffle their feet in such an area as opposed to walking normally. This phenomenon has been known to result in the death of cows because of the greater distance between their front and rear hooves and hence greater potential difference.

So why don't they stand on one leg?

I hate uncleared earth faults and all the trouble they cause.

Have you ever seen a cow stand on one leg?

Yes, but she did have a pretty face.

Just turn up the juice a little more....