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Join Date: May 2015
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Coefficient of Performance

10/01/2018 10:45 AM

Respected all,

Request you to kindly help in giving explanation to the below statement:

"When a building is heated it is suggested that 3 kWh of heat, 1.5 kWh of fuel and 1kWh of electricity have the same value."

How could this be possible?

Thanks in advance,

Regards

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Guru

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#1

Re: COP

10/01/2018 10:53 AM

Sounds like either an energy efficiency or economics question. Do either make sense for your source of the quote?

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#2

Re: COP

10/01/2018 11:53 AM

"The coefficient of performance or COP of a heat pump, refrigerator or air conditioning system is a ratio of useful heating or cooling provided to work required."..

So it's a calculation of efficiency of your system in providing or removing, useful heat, that's the heat flowing from the system into your living space, or heat existing in your living space, not including, in the case of gas or oil burners, heat that is exhausted from the stack...so the efficiency of your system moving heat 'in to' or 'out of', your living space...

So electric heat is nearly 100% efficient...the others are not because of waste heat...but the cost per btu of different fuels varies...

https://en.wikipedia.org/wiki/Coefficient_of_performance

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#4
In reply to #2

Re: COP

10/01/2018 3:39 PM

"Kilowatthour generated per unit of fuel used = Fuel heat content (in Btu per physical unit) divided by Heat rate (in Btu per kWh)"....

"To express the efficiency of a generator or power plant as a percentage, divide the equivalent Btu content of a kWh of electricity (3,412 Btu) by the heat rate. For example, if the heat rate is 10,500 Btu, the efficiency is 33%. If the heat rate is 7,500 Btu, the efficiency is 45%."...

https://www.eia.gov/tools/faqs/faq.php?id=667&t=6

https://www.eia.gov/tools/faqs/faq.php?id=107&t=3

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#3

Re: COP

10/01/2018 2:42 PM

...which means that the COP on <...fuel...> is 2 and the COP on <...electricity...> is 3.

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#5

Re: Coefficient of Performance

10/04/2018 12:51 PM

The short answer is you can use electricity to run a heat pump. The total output of heat (to heat the building) is the energy (work) supplied by the electricity plus the amount of heat pumped from outside. This total is greater than the electricity supplied.

If the energy (work) for the heat pump is supplied by combusting fuel, there is a loss of efficiency compared with electricity.

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/heatpump.html

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