Rating of Pump

What are the tank sizes and how fast do you want to fill them? ...and with what?

10 tanks of 1000 gallons of water each in one hour would require a pump rated at ~170 gpm...this would require a motor of about 3-4 hp...but then you have to take into account the head, fluid viscosity and other variable factors...

Then again if the tanks were 10,000 gallons each and you wanted to fill them in an hour, that would require 1700 gpm and about 30 hp , depending on variable factors...

If the tanks are downhill from your source then a simple siphon can eventually fill 10 tanks of various sizes without the need of any motor.

Now think about what information you are forgetting to tell us.

A 42 horsepower pump should do the trick.

42 is always the answer...

In fact oddly enough, it’s 42 kW as well! Physics be damned...

Actually in Australia it is 46.2 because everything has GST, goods and services tax, added, even the meaning of life.

Ask a pump supplier, after you define the work the pump has to do!

Too obtain the rating of the pump,first use a medical syringe,calibrated in ml to fill one of the tanks to determine the volume of the tank.

Multiply this number by 10,if all tanks are identical in volume and at the same level.

Then determine how fast you wish to fill the tanks.

Calculate the positive or negative head the pump will experience,considering the elevation of the pump in relation to the tank,and the entry point of the liquid into the tank.

For instance,if you are filling a vertical cylindrical tank from the bottom,positive head will increase as the level rises,but if you fill from the top,it will be a constant positive head pressure.

Determine the supply voltage and current available to power the pump.

Consult a pump manufacturer's chart to make your choice.

After you have determined the pump size,determine the conductor size to supply the pump,the short circuit protection for the conductors, the bonding and grounding requirements,the thermal overload protection for the motor,the pump control circuit,whether manual or automatic,or software controlled, the control logic if using a PLC or SCADA.

Good luck.

Reciprocating - is this an oil well?

Most of the question did not arrive, please give it.

It's about the same.

Multiply the pressure rise through the pump by the flowrate, which gives the required shaft work, and divide by the efficiency of the pump/motor combo to get the input power requirements.

Then it's just a case of converting the units of the answer by some factor to get <..._HP...>.

"Simples. ζ"

Pq=pgQH

Pq - Power transmitted to the pumped fluid in kW

p - density of pumped medium

g - gravitational acceleration constant (9.81)

Q - capacity - in m3/s

H - head in m

Motor power required P=Pq/pump efficiency.

Installed motor power would typically be between 10 to 25% greater than P depending on duty and size.