If two different borewell pumps at different locations one with 1.5 kw at 400 ft depth and the other one with 3.75 kw at 800 ft depth operated, both having same ground water level what will be the savings expected if only 1.5 kw pump is operated.
It depends upon the levels in each borehole above each pump and the height to which these two different <...borewell pumps...> lift; this information has been withheld from the forum. So, assuming that the figures above are the total lift in each case:
The <...400 ft...> one will produce no more than [tap, tap, tap, press equals...] 4.5m3/h, ignoring pump efficiency for the moment.
The <...800 ft...> one will produce no more than [tap, tap, tap, press equals...] 22m3/h, ignoring pump efficiency for the moment.
So the water saving will be around [tap, tap, tap, press equals...] 84% compared to having both pumps running.
Again, ignoring efficiency and assuming the pumps are running at their rated electrical load, the power consumed will be around 28% of what it was having both pumps running, by simple arithmetic.
What's the prize, please?
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Using 80% less water, you would expect lower energy consumption, but I wouldn't characterize this as saving....Now if you could supply as much water with less energy, then you would be saving....but if you don't need that much water to begin with, then you are wasting both water and energy....If on the other hand you need that much water, and are curtailing use, then you are not saving, you are sacrificing...
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Why is a <...Power consumption...> thread in the Mechanical Engineering section?
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"Did you get my e-mail?" - "The biggest problem in communication is the illusion that it has taken place" - George Bernard Shaw, 1856
Question is a bit vague as you do not say whether the powers you have given are the "size" of the motors or the drawn power, but if the groundwater level is the same for each pump then the differential head will be the same for each pump.
Power = þghQ. Specific gravity (Rho), g and total head are all equal, so Q is the only variable. If the pumps are identical then Q is also equal.
3.75 - 1.5 = ?
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