Electrical Motor Chain Driven Conveyor Output

I work it out as 5.996 revolutions per carrier, but not knowing the number of carriers makes it a bit hard to work out the cycle time for the conveyor.

ie: 145.5 / (pi x d) = 5.996 revs per carrier.

9.65/ 5.996 = 1.609 carriers per minute.

I assume the gear box output sprocket is driving another sprocket mounted on overhead conveyor which provides lateral movement to conveyor. In this case or otherwise also, First calculate the peripheral speed that will be available to the conveyor. This will depend on the ratio of Driven / Drive sprocket which is unknown here. Once you get the ratio right, calculate the peripheral speed Pi x d. This will give you an indication of travel of conveyor for one rotation of drive sprocket. In case, the ratio is unity (1) or, if the drive sprocket is driving the conveyor directly, peripheral speed will be 3.14x7.723 = 24.25" (travel of conveyor).

If now you divide travel distance 145.5 by peripheral speed you get no. of rotations of sprocet required to achieve this travel i.e., 145.5/24.25=6 (rotations)

If you multiply peripheral speed (24.25) by 9.65 rpm, you get the travel achieved in one minute i.e., 24.25x9.65=234"

for travel of 145.5, you will consume 145.5x60/234=37.3 Seconds