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Thermodynamic Losses in Prds

03/14/2008 5:29 AM

I am trying to depressurise and desuperheat steam from 176bar, 540deg C of approx flow 180t/h to 105bar, 515deg C. This is done to condition the steam parameter suitable for the inlet of a Steam Turbine. I need to evaluate the loss as a result of this depressurising and desuperheating. How is it done?

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#1

Re: Thermodynamic losses in prds

03/14/2008 5:58 AM

At 176bar,540 deg C, the enthalpy is h=3392.32 kJ/kg.

At 105bar,515 dec C, the enthalpy is h=3406.80 kJ/kg.

The change in enthalpy is -14.48 kJ/kg; 735 kW (14.48 kJ/kg * 180 tons/hr)

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#2

Re: Thermodynamic losses in prds

03/14/2008 6:16 AM

From steam tables:

  • h(180barg, 500degC) = 3268kJ/kg
  • h(180barg, 600degC) = 3555kJ/kg
  • h(170barg, 500degC) = 3281kJ/kg
  • h(170barg, 600degC) = 3564kJ/kg.

Interpolating, the start condition is: h(176bar, 540degC) ≈ 3387kJ/kg.

Steam at all the above temperatures and pressures is superheated.

From steam tables:

  • h(110barg, 600degC) = 3616kJ/kg
  • h(110barg, 500degC) = 3360kJ/kg
  • h(100barg, 600degC) = 3624kJ/kg
  • h(100barg, 500degC) = 3373kJ/kg

Interpolating, the end condition is: h(105bar, 515degC) ≈ 3404kJ/kg.

So energy needs to be added to get it to this condition: 3404-3387=17kJ/kg. It cannot get there by adiabatic expansion. At these end conditions, the steam is still superheated.

Er, around 800kW is needed.

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#3
In reply to #2

Re: Thermodynamic losses in prds

03/16/2008 11:59 PM

Thanks. got the idea, shall continue from here.

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#4
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Re: Thermodynamic losses in prds

03/17/2008 12:48 AM

From the calculation which is shown and according to what i did, its not evident that there is a loss of energy from inlet to outlet condition, as the specific enthalpy is increasing. Its obvious that the depressurising and detempering is a thermodynamic loss. Is there a method to show this loss.

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#5
In reply to #4

Re: Thermodynamic losses in prds

03/17/2008 6:07 AM

Yes. Calculations based on the data in Steam Tables!

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#6

Re: Thermodynamic Losses in Prds

08/14/2011 1:25 PM

Dear Mr. Gautamkum,

As I nderstand from Your Question, IT is NOT CLEAR or defined correctly. You have referred " I need to evaluate the loss as a result of this depressurising and desuperheating,"

Which loss you want to evaluate.? What is the Temperature of De-Superheating water used.?

As already explained by other CR4 MEMBERS, the Difference in ENTHALPY/Kg. of Steam can be found out before de-superheating and after de-superheating and this quantity to be multiplied by 180x1000 Kgs. and this heat will be absorbed by the de-super heating water pumped/sprayed and the total quantity of de-superheated steam , will be obviously more.

Neglecting the RADIATION LOSSES (for discussions purpose) where is the question of "loss" that is to be estimated.?

Pl. clarify

RAJESWARI.

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