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Anonymous Poster

Fault Level

06/04/2008 11:20 PM

hi,

iam an electrical technical officer. got no qulification certificate or anythings, just base on my experiance. just wondering what this fault level that so important when designing power distribution. am always been asking by my senior on this. cant answer him correctly. and how to calculate it?

thanks for any respond and especially knowladge.

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#1

Re: Fault Level

06/05/2008 12:13 AM

Kindly register yourself and identyfy, give your email id, the brief write up on fault level etc can be sent to you.

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#2

Re: Fault Level

06/05/2008 12:24 AM

<cringe>

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Anonymous Poster
#3

Re: Fault Level

06/05/2008 1:07 AM

The fault level at a point is that current which would have caused 100% voltage drop, upto that point, in case, a bolted-type-arcless zero resistance short-circuit is created at that point.

An example - A system fault level at a point is 125 MVA. Then system impedance upto the point is 1/125 = 0.008 p.u. per MVA or 100/125 = 0.8% per MVA.

Dear guest nothing is difficult to learn - there should be desire in you to learn. However to learn this subject your basic understanding of AC system is necessary and good knowledge of mathematics. Short circuit calculations are simple provided basic knowledge is gathered.

Do not hesitate to identify yourself. The forum tries it best to help all.

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Guru
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#4

Re: Fault Level

06/05/2008 2:40 AM

Tell your employer, if he sends you on a basic relevant study course it will benefit both of you and you will then be able to answer his question.

Find the course you wish to attend first (prefferably day release with maybe an evening class too)

Most of my education relevant to Electronics was done like this.

Del

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#5

Re: Fault Level

06/05/2008 3:02 AM

Job-related training is an important investment for any business.

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Anonymous Poster
#6

Re: Fault Level

06/06/2008 12:55 AM

Fault Lvl Calculation :

01. Main Xmr - 6 MVA , 66/11 KVA , 7.75 % impedence.

02. Cable 300 sqmm, HT , XLPE - 20 mtr.

First convert all component in to per unit MVA rating.

(A) Xmr 6000 KVA :-

MVA value = MVA rating / Impidence (Z)

MVA value = 6 / 0.0775 = 77.41 MVA

(B) 66 KV Cable MVA :- MVA Value = MVxMV / Z

MVA Value = .066x.066 / 0.002, assuming Cable impidence is 0.2,

MVA Value for cable = 2.178 MVA

Total System MVA ( Fault level ) = A + B = 77.41+2.178 = 79.588 MVA say 80 MVA

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#7

Re: Fault Level

06/06/2008 2:51 AM

It's important because it tells you what the maximum current will be if there is a total short circuit in the circuit. It depends on the impedance of the supply alternator, transformers and feeder cables.

Imagine a forklift rams its tines into a factory distribution board just above the local circuit breaker. For a short time (before the main board's protection acts) there will be a huge current (the fault level) and this may cause significant heating or mechanical effects ie melting terminals or ripping the cables from the cable tray.

The high fault current can also cause arcing as the contacts open, the arc burns the circuit breaker and the resultant gases allow the arc to continue, etc followed by BANG! the switchboard blows up.

Circuit breakers have a fault rating that they guarantee to break without damage.

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