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Participant

Join Date: Jun 2008
Posts: 4

Cable selection for AC & DC application

06/12/2008 6:16 AM

Can i use the same cable ampacity and R & X value of a particular cable for both AC & DC application? In case no then what is the method. I have taken care other cable selection criteria like various derating factor for cable laying formaion, ambient temperature, short circuit, voltage drop consideration etc.

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Anonymous Poster
#1

Re: Cable selection for AC & DC application

06/12/2008 7:01 AM
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Anonymous Poster
#2

Re: Cable selection for AC & DC application

06/13/2008 12:44 AM

When you accidentally duplicate posts, you can always click the Report button on the "offending-post" page and request it to be removed.

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#3

Re: Cable selection for AC & DC application

06/14/2008 2:15 AM

Can i use the same cable ampacity

Yes if you are meaning same RMS values

RMS=root mean square

So Square Idc=Square Irms ac.

And that is what dissipates inside cable-and heats up the cable isulation etc--the limiting criterion.

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Participant

Join Date: Jun 2008
Posts: 4
#4
In reply to #3

Re: Cable selection for AC & DC application

06/15/2008 12:40 AM

Thanks. I would like to elaborate my question. I am using standard cable ampacity table of a particular cable manufacturer for my use. This ampacity shown in the table is in which form AC or DC. Can i consider cable ampacity for a particular size of the cable irrelevent to the application i.e. AC or DC.

Let's say a cable manufacturer provides a cable ampacity table and according to it 2C X 16 sq. mm. copper cable ampacity in air is 115 amps. My question is can i consider same current for the AC or DC application? This 115 amps current is in which form?

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Participant

Join Date: Jun 2008
Posts: 4
#5
In reply to #4

Re: Cable selection for AC & DC application

06/15/2008 3:46 AM

I mean do we require to perform following equation to get the equivalent Idc value from the cable ampacity chart of a given cable of a given manufacturer

Idc = Iac x √s where

Idc = DC ampacity

Iac = AC ampacity at 50 Hz

s = Skin effect ratio at 50 Hz

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Anonymous Poster
#6
In reply to #5

Re: Cable selection for AC & DC application

06/15/2008 5:11 AM

The mfr would normally state the tested, true nominal amps capacity of the cable...they would naturally expect that - and feel most immunized against liability since - the cable will be derated to a specific application. Therefore, divide nominal cable amp carrying capacity by 0.707 RMS approximation factor to obtain capacity for AC application.

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Participant

Join Date: Jun 2008
Posts: 4
#7
In reply to #6

Re: Cable selection for AC & DC application

06/15/2008 6:54 AM

Hello friend,

I am not worried about the derating factor for the cable size as the same i have taken care as i stated earlier. I am concerned about the base current which i should consider for AC and DC application.

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Anonymous Poster
#8
In reply to #7

Re: Cable selection for AC & DC application

06/15/2008 4:53 PM
Thanks. One could reasonably expect that the same principle would apply...and that from a mfr's point of view. You said before (with suggestions interjected):
  • I am using standard cable ampacity table [supplied by] a particular cable manufacturer for my use. [supplied by the manufacturer providing my cable?] This ampacity shown in the table is in which form AC or DC[?]. Can i consider cable ampacity for a particular size of the cable {irrespective of] the [my] application, whether it's AC or DC?
    • Perhaps part of the dilemma pertains to whether that manufacturer's chart data pertains to their own cables or to any cable--in effect, the source of the chart data.
      • Probably the chart is generic (and parameter dependend, not application dependent), applicable to that or manufacturer's cables of similar or like manufacture.
    • When you say "irrespective," you are implying equivalency of carried current (and so is manufacturer's provided chart)...which means, in order to be equivalent (whether for purpose of nominal current as between AC and DC) the currents would need to be normalized to a mean net current flow the cable is expected to carry. If AC RMS value is .7 of DC, the cable could carry a higher nominal AC current...which has equivalent net current to DC.
      • In effect, when you determine RMS for the (higher) AC current, you have equalized the net (nominal) current that the cable is specified to carry to supply a load.
  • Let's say a cable manufacturer provides a cable ampacity table and according to it 2C X 16 sq. mm. copper cable ampacity in air is 115 amps. My question is can i consider same current for the AC or DC application? This 115 amps current is in which form?
    • Because your source is a chart which provides current in terms of cable property and dimensional parameters (as opposed to cable branding which might be application specific) it can reasonably be concluded that it (the 115A example) is in the form of current throughput, per se, as drawn by combined loads; which is to say, an AC or DC current value provided these are equalized with respect to application load(s).
      • However, this could be different if solely using markings on the cable (when not resorting to cable parameter chart), in which case a manufacturer (or someone seeing your question posted in the CR4 manufacturing section, would (or might) have a more uneqivocal answer.
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