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3Doug
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Another Triangle Challenge (with a twist)

10/04/2008 4:30 PM

Ok, the triangle challenges are fun, but the ones I've seen are based on a upward pointing equilateral triangle divided into subsections. To make one a bit more challenging, I've decided to do this:

So, how many triangles can you find?

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Kilgore Trout
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#1

Re: Another Triangle Challenge (with a twist)

10/04/2008 4:52 PM

23?---Had to cover one eye and I think I hurt it.

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3Doug
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#4
In reply to #1

Re: Another Triangle Challenge (with a twist)

10/04/2008 10:31 PM

EH! No fair peeking!

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Kilgore Trout
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#5
In reply to #4

Re: Another Triangle Challenge (with a twist)

10/05/2008 12:01 AM

ouch ouch ouch ouch ouch ouch ouch ouch ouch ouch.

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Keywalker
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#2

Re: Another Triangle Challenge (with a twist)

10/04/2008 7:13 PM

As far as I can tell the answer is 23 no matter how you tilt your head.

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cnpower
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#3
In reply to #2

Re: Another Triangle Challenge (with a twist)

10/04/2008 9:00 PM

hehe
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rakesh_semwal
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#6

Re: Another Triangle Challenge (with a twist)

10/05/2008 5:42 AM

Try this too in parallel
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cnpower
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#8
In reply to #6

Re: Another Triangle Challenge (with a twist)

10/08/2008 5:20 AM

http://cr4.globalspec.com/thread/27313#comment289944

55?
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rakesh_semwal
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#9
In reply to #8

Re: Another Triangle Challenge (with a twist)

10/08/2008 5:43 AM

Cn I have already counted 100+ but lost position,
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cnpower
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#10
In reply to #9

Re: Another Triangle Challenge (with a twist)

10/08/2008 7:14 AM

count?

my god, it soon make you dizziness and giddness. you will confuse soon.

I try to do like this, 1+3+9+

--------------...........1+3+9+

-------------................1+3+9+

-------------.............................3x2+1

.............................----------------------

= 55

its only a n estimation value, it may belong to a issue of number theory. and Im out of door to this subject.

as to the top thread, you can work out like this.

count all points, use composition method ( every 3 points from N points) C83- 2x4 -7=
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cnpower
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#11
In reply to #10

Re: Another Triangle Challenge (with a twist)

10/08/2008 7:21 AM

41
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cnpower
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#12
In reply to #11

Re: Another Triangle Challenge (with a twist)

10/08/2008 7:39 AM

41-10=31

or calculate like this,

C82-4+1+6=31
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cnpower
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#13
In reply to #12

Re: Another Triangle Challenge (with a twist)

10/08/2008 9:20 AM

I check and find above is wrong.

it should be"

2xC42 + C32 + 3xC32 - 2 + 1 = 23
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#19
In reply to #12

Re: Another Triangle Challenge (with a twist)

08/19/2009 11:34 PM

You mean:

CnPower - for 1 sex?
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bwire
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#7

Re: Another Triangle Challenge (with a twist)

10/07/2008 1:27 AM

25

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3Doug
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#14

Re: Another Triangle Challenge (with a twist)

10/08/2008 3:42 PM

Well, Kilgore Trout, Keywalker, and cnpower get to share the great big no-prize!

Here's the visual solution I worked up, in a more typical orientation:

I began by showing triangles formed by a single section, then 2 sections, etc, until all that was left was the main triangle.

The winners can pick up their no-prize on the 2nd Tuesday of next week, of course, after paying a small processing fee.

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Kilgore Trout
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#15
In reply to #14

Re: Another Triangle Challenge (with a twist)

10/08/2008 10:21 PM

Excellent! I have a no shelf to put it on. I just want to thank my coach and say hi to my mom--Hi, mom, I love you.

Wow this is great!

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cnpower
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#16
In reply to #14

Re: Another Triangle Challenge (with a twist)

10/09/2008 7:06 AM

wow, you have time to count one by one.

Try to cont Reksh's trangulars, I can nt work out.
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markalfredsteele
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#17

Re: Another Triangle Challenge (with a twist)

10/09/2008 7:20 PM

9

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markalfredsteele
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#18

Re: Another Triangle Challenge (with a twist)

08/18/2009 6:03 PM

eleven

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