about load calculations

Is this an examination from your employer? or homework?

Is this an examination from your employer? or homework?

Hi,

this is not an examination or a test, I just want to compare the calculations I made because im new to three phase circuits and im not sure of my calculated values..The information that i will obtain will also serve as my reference for the further study of three phase ckts. I hope you can help me with that..

Thanks...

Ok, in fact, lots of guys could help you with it.

first, your condition is insaficent. so you should complement them.

amuse your work machine get power as point as you list, the load is above, the PF will be 1, its only ideal.

second, from delta to Y, the voltage will have /3 relation (1.732) so the voltage iwll be 220/380, if you use 240v , then line voltage will be 1.732x240, you can calculate yourself.

so check your condition then put out.

please see,

total connected load= 74.23 KW

Power factor (lighting (1 - 0.9)) , (other service (0.8))

Diversity factor (lighting = 90%)(receptacle=70%)(HVAC=80%)(water heater=80%)

Demand Load = Diversity factor X Connected Load

Max. Demand Current = Demand Load / (380 x 1.73)

with my regards

Eng. Ali. sh.