Hello all, Please walk this through with me.
Im not an engineer but I am interested in solving this problem.My goal is to know how much concrete materials I will use (cement, agg, sand).
I have an abundance of all materials here on my site. My slab is 6 inch thick, 5x10 meters. Ive calculated total cubic yards= 10, covert to cubic meters =7.6.
So our ratio is 300 kg agg, 200 kg sand, 100 kg cement.
I have a Silo full of cement I can take, how much cement to drain for my project?
Getting numbers off the web, relative density of water is 1000kg, aggregates are between 2.4-2.9 (say 2.6), Cement is 3.15, water/cement ratio is .40.
I found this on the net:
V a = W L / ( SG ) W u
where V a = absolute volume, ft 3 (m 3 )
W L = weight of material, lb (kg)
S G = specific gravity of the material
W u = density of water at atmospheric conditions (62.4 lb/ft 3 1000 kg /m 3 )
Then, job yield equals the sum of V a for cement, gravel, sand, and water.
Ok so all Relative densities= 6.15
6.15 x (1000kg for water)= 6150
600/ 6150=.097
Is this correct? Im a little confused if I did this correct. The answer would have me almost 1 cubic meter per mix. S0 I would need to drain about 760 kg from my silo?
Can someone please hep me?
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