Higher Frequency Ranges, Signal Losses and Distortion

Some idea as to the frequency ranges involved, the transmission medium and the type of distortion would certainly be more likely to get you a useful answer.

If you want information, you have to be willing to prime the pump a bit.

Noise interference from electronic devices has a great effect on the HF bands

Broadband over power lines -BPL internet access is believed to have an almost destructive effect on HF communications. This is due to the frequencies on which BPL operates (typically corresponding with the HF band) and the tendency for the BPL "signal" to leak from power lines.

That's just the nature of RF. The higher the frequency the greater the loss. TV channel 2 has a wave length of on the order of about 6 feet while a wireless computer card's wave length is something like 32 centimeters . Long wave lengths just travel farther. If you don't understand logarithms you basically just accept this as fact and go on, because trying to understand it will just make you crazy.

RF & Microwave signals require a matched impedance and low loss materials for efficient and "distortion minimized" transmission of the electromagnetic energy. The the losses (reflected, dissipated & absobed) vary proportionately with the frequency (inversly with the wavelength). This is because the precision of the mechanical dimmensions and/or performance of the conductive and insulating materials of a fixed transmission line represent an increasingly greater mismatch loss (reflected), material loss (absorbed and converted to heat) and shielding loss (dissipated outside of the tramsmission line) to increasingly higher frequency signals. More of the energy of a higher frequency signal propagating through air will be absorbed, distorted or reflected (due to atmospherics). The formulas and proof of this phenomenon requires a high order of math and physis to understand and apply to the real world.