capacitive charging current of a cable?

For calculating the capacitive current you need:

I=measured current

pf=0.1

it goes like: Icapacitive=sqrt(I-(I/pf)²)

Icapacitive is the capacitive current in open circuit.

the I/pf is the active component of the current, consumed in open circuit beacuse the electrical resistance if the insulation is not infinitely large.

correction:

Icapacitive=sqrt(I²-(I/pf)²)

sqrt(I²-(I/pf)²)

I²<(I/pf)²

eg:- If I=10 & pf=.1

I²=100 & (I/pf)²=10000

Is it Possible?............

right. Sorry .

The thing was actually : Icap=I*sqrt(1-pf²)

where: I=measured current

pf- power factor

Icap= needed current

thanx

Use a scope to measure the rise time of the cable when a battery is suddenly applied.

Measure the capacitance of the cable with a meter or bridge. The R can now be calculated using t=RC. Now divide the voltage waveform from step one by R to get the current waveform. I think that will be the charging current that you are asking for.

Sorry; I need to add more to my answer:

For a transient voltage, the current flow will be the derivative of the voltage wave, ( i=dV/dt). So after capturing the voltage transient, take it's derivative and plot that.