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Power-User

Join Date: Feb 2009
Location: India
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Unanchored Tanks and API 650

06/08/2009 6:21 AM

The clause no E4.1 of API 650 FOR TANKS, has the following words"..or for unanchored tanks, the weight of the portion of the contents adjascent to the shell"

What is the maening? What is the volume of the tank content to be considered? Pl clarify

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Associate

Join Date: Jan 2009
Location: Thailand
Posts: 42
#1

Re: API 650 Tanks

06/08/2009 8:20 AM

Could you please explain your question again

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Power-User

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#4
In reply to #1

Re: API 650 Tanks

06/09/2009 12:48 AM

My question was what is the definition of the "weight of the content adjascent to the shell" ? How this is calculated?

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Anonymous Poster
#2

Re: Unanchored Tanks and API 650

06/08/2009 10:28 AM

Read a bit further to get the equation for calculating this; it is the allowed weight of tank steel and contents to resist overturning moments.

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Power-User

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#3
In reply to #2

Re: Unanchored Tanks and API 650

06/09/2009 12:46 AM

The further calculation formula does not talk about the weight of the content. The weight of the content should be added to the weight of the tank to match with the over turning moment.

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Power-User

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#5
In reply to #3

Re: Unanchored Tanks and API 650

06/09/2009 1:04 AM

wL = 7.9tb√(FbyGH)

Where:

wL = maximum weight of the tank contents that may be used to resist the shell overturning moment, in lbf/ft of shell circumference.

(the units don't work out because the equation is empirical based)

(and this may be significant if you are designing a new tank - you seem to be using an older edition of API 650 - 10th or earlier, because the latest 11th edition has this clause in E6.2.1.1 - API 650 is a VERY dynamic code)

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Power-User

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#6
In reply to #5

Re: Unanchored Tanks and API 650

06/09/2009 1:34 AM

thanks. Your reply made the code more clear to me

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Participant

Join Date: Feb 2011
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#7
In reply to #5

Re: Unanchored Tanks and API 650

04/26/2011 1:33 AM

How to calculate MF - moment about the shell to bottom joint from liquid weight

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