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hi everybody, i want to know how to calculate the pressure required to lift a 500 kg of motor........
I think your question became truncated somewhat!!
If you mean you need to know the pressure in a hydraulic piston to lift 500kg...
Then its simply the cross sectional area of the piston you need to know...
If the piston were 1 cm^2 then you would need a pressure of at least 500 / 1 = 500 kg/cm^2...
Or if Masu is around and wanting his force units!
It would roughly be 5000 N/cm^2..
John.
v need it 4 both.....i think the same method will be followed in pneumatics also.......
Yes, it's just basic pressure definition:
P = F x A where, using SI:
P = pressure [Pa, or N/m2]
F = force [N]
A = area [m2]
Any specific problem with it?
The only difference between hydraulics and pneumatics is that air is compressible, and you'd normally use far lower pressures, larger areas, but frequently higher speeds.