Previous in Forum: Watts and Electrical Connectors   Next in Forum: How do we detect Islanding of generator from mains without mains breaker status?
Close
Close
Close
4 comments
Rate Comments: Nested
Participant

Join Date: Nov 2009
Posts: 1

Power Measurements

11/16/2009 3:42 PM

Can mesuring required power (kw) for driving pump ,from mesuring electrical power parameters of cupleted motor ?

why? for proofing electrical consumption.

Register to Reply
Interested in this topic? By joining CR4 you can "subscribe" to
this discussion and receive notification when new comments are added.
Guru
United States - Member - New Member

Join Date: Jun 2008
Location: Alabama
Posts: 1604
Good Answers: 63
#1

Re: Power Measurements

11/16/2009 5:53 PM

"Can mesuring required power (kw) for driving pump ,from mesuring electrical power parameters of cupleted motor ?" Yes

"why? for proofing electrical consumption." If the motors are the same you should get a close estimate of the kw usage.

Register to Reply
Guru
United Kingdom - Member - Indeterminate Engineering Fields - Control Engineering - New Member

Join Date: Jan 2007
Location: In the bothy, 7 chains down the line from Dodman's Lane level crossing, in the nation formerly known as Great Britain. Kettle's on.
Posts: 32175
Good Answers: 839
#2

Re: Power Measurements

11/17/2009 3:01 AM

The power required for any fluid mover is the volumetric flowrate multiplied by the pressure rise divided by the efficiency.

__________________
"Did you get my e-mail?" - "The biggest problem in communication is the illusion that it has taken place" - George Bernard Shaw, 1856
Register to Reply
Guru

Join Date: Oct 2009
Posts: 2061
Good Answers: 169
#3

Re: Power Measurements

11/17/2009 9:59 AM

Pump HP = {(Specific gravity of the fluid being pumped x Head x Flow rate)

/ (K x Efficiency of the pump)

The constant 'K' depnds upon the units of flow rate, head & specific gravity.

From this you can cross check the power required for doing the required pumping work. Divide this by the motor efficiency, that will give you the motor HP.

Register to Reply
Power-User

Join Date: Jul 2008
Location: UK
Posts: 205
Good Answers: 50
#4
In reply to #3

Re: Power Measurements

11/18/2009 2:28 PM

The motor nameplate HP is its rated output mechanical power so there's no need to divide by motor efficiency, its already taken into account.

Just take the pump required power and select the motor accordingly.

__________________
Something new every day!
Register to Reply
Register to Reply 4 comments
Copy to Clipboard

Users who posted comments:

electricalexpert65 (1); MalcolmK (1); PWSlack (1); wareagle (1)

Previous in Forum: Watts and Electrical Connectors   Next in Forum: How do we detect Islanding of generator from mains without mains breaker status?

Advertisement