Electric Motor - Need Winding Help

http://www.bing.com/search?q=WEG+motor+&src=IE-SearchBox&Form=IE8SRC

not helpful

Is this a rewinding job?

Yes

And the reason the motor hasn't been returned to the manufacturer for this operation is what, please?

I dont want to return as i am rewinding the motor. I just want help in the rewinding data..

Take all details, frame, model, serial number, year manufactured and send to tiagom@weg.net , maybe he can help you.

He is the sales manager. If he not help, ask me again.

Thanks Amendes. I will contact tiagom. Your help is very much appricated.

Thanks

Thank you very much rudy, I am going to use span 1-11 for two layer winding.

Thanks

Read the information in this link and apply the knowledge.

http://www.uiitraining.com/b51a/100/15104ac_motor_rewind_intro1.htm

Thanks Rudy, this is not clear. Can you send it on my email---kuldipkenya@hotmail.co.uk

Thanks

your mail is on its way

greets

thanks got it. cheers

In support of what Rudy has given to u,kindly meet motor rewinding specialists in yr locality and they would give u instant solution.Even if u hv to pay something,its worth the job and good result u need.They have lots of motor rewinding datas.

U can also contact WEG if u hv their address or web.My local rewinder rewinds all my WEG motors and they perform very well.

Patrick Whowha

Thanks Patrick, i have a rewinding company but this was a one off. Check my website--www.nakuruindustrialrewinders.com

Thanks

Re: Electric Motor - Need Winding Help

I have a 22kw WEG motor 6pole 72 slots 3phase. I have lost the windings details. Can anyone tell me what coil span (pitch) i can use? Am thinking of using 1-11 span group of 4 coils 18 SETS. Is this ok. Urgent please. Thanks in advance

Dear kuldipkenya

I will try to calculated with reference to the following literatures :

1. A. Shanmugasundaram, G Gangadharan, R Palani. Electrical Machine Design Data Book

2. IJ Nagrath, DP Kothori, Electrical Machines

3. MK Sibal. Electrical Machine Design and Machine Drawing

4. V.N. Mitle. A. Mittal. Design of Electrical Machines

5. AK Shawny. Electrical Machine Design

Data:

Slot = 72

Pole = 6

( SPP ) Slot / pole / ph = (72/ 18) = 4 slot

Slot / ph (g ) `` = 72 / 3 = 24

Coil pitch for full pitch = Slot / pole = 72 / 6 = 12

Its mean the coil span will be = 1 – 13

Slot angle (α ) = ∏P / Slot

∏ = 180 ( North to South )

Slot Angle (α) =( 180 x 6 ) / 72 = 15 deg elect

Normally to reduce of harmonic the pitch winding will be used a chording factor.

Possibility of chording factor for SPP = 4

Coil pitch (kp) = ¾ with pitch factor = 0.991

Coil pitch (kp) = Cos ( α / 2)

Thus, the coil pitch will be = 1800 elct – α

= 180⁰ elct – 15⁰elct = 165⁰elct

= 165⁰elct / 15⁰elct = 11 slot

Coil span = 1 - 12

Distribution factor (kd) = (Sin (mα)/2) / m Sin (α/2)

m = SPP = Slot/pole/ph = 4

=( Sin (4x15)/2) / 4 Sin (15/2) = 0.5 / 0.522 = 0.9577

Winding Factor (kw) = kp x kd = 0.991 x 0.9577 = 0.9491

Basic formulae:

D2L = KW / ( Co x N )

KW = Motor Out Put

E = 4.44 x kw x f x T1 x Øm

Ø per pole = ( Bav x ∏ x D x L ) / P

Bav = Flux density

D = diameter of core

L = Length of core

P = pole

Let say :

D = 0.3 M and L/D max = 0.65, L = 0.2 m

Bav = 0.489 Wb / M2 for class F

Ø per pole = ( 0.489 WB/M2 x ∏ x 0.3M x 0.2M ) / 6

= 0.0922 / 6 = 0.015 WB

E = 380 VOLTS

F = 50 HZ

kw = 0.9491 ( winding factor)

T1 = E1 / ( 4.44 x kw x f x Øm )

T1 = 380 / ( 4.44 x 0.9491 x 50 x 0.05 ) = 380 / 3.16 = 120 turn

Slot / phase (g ) = 72 / 3 = 24

If Winding is double layer

No of conductor in the slot =( T1 x 2 ) / g = ( 120 x 2 ) / 24 = 10 turn

Synchronous Speed = 1000 RPM

Let say for the cooling with speed = 1000 RPM, Current Carrying Capacity for 1mm2 = 4 Amps

The cross section of conductor will be :

If Cos ф = 0.85

Current IFL = 22 kW / ( √3 x 0.85 x 380 ) = 39.3 Amps app = 40 Amps

Wire size to accommodate of IFL with 1 mm2 = 4 Amps

Wire size = 40 amps / 4 amps = 10 mm2

Wire Cross Section Area (q ) = (1 / 4) x ∏ D²

Wire Diameter ( D² ) = 4 q / ∏ = 4 x 10 / ( 3.14 = 12.7 mm2

Wire Diameter (D) = √12.7 mm² = 3.5 mm

Rgds

sis

Thank You Siswanto,

I used span 1-11 double layer and the motor is doing fine.

Thank You

Kuldip