Please help me out to solve this :- I did some calculation but i donot know is it ok or not
Design Temp=120 degree c= 248 F
Design Pressure= 1.0 kg/sqcm/FV= 14.233 psi
Joint Efficiency = 0.7
Corrosion Allowance = 3mm.
Material = IS 2062 Gr.B
CST OD= 2200 mm.
CST THK assumed = 10 mm.
CST ID= 2180 mm.
Distance Between Stiffener = 3000 mm.
Max Allowable Stress = 20000 Psi
CST Inner Radius = 1090 mm.
For internal Pressure UG-27
Case 1= Circumferential Stress
t= PR/SE-0.6P
t=1.10803 mm.
Reqd t= 1.10803+ CA= 1.10803+3=4.1080 mm.
Case 2= Longitudinal Stress
t=PR/2SE+.4P
t=0.553mm.
Reqd t= 0.553+ CA= 0.5535+3=3.5535 mm.
Hence thickness 10 is ok for internal pressure .
Now for External Pressure (where i got prob in finding Exact Value of A & B)
UG-28
CST t=10 mm (Assumed)
Corrosion Allowance = 3 mm.
so t become = 10-3*2=4 mm.
Do/t= 550
L/do=1.36
Value of A Which I find is = .000068
Now A fall on left of material / temp curve so i have to calculate value according to
Pa= 2AE/3(Do/t)
E= 200 Gpa =29007500 psi
Pa= 2*0.000068*29007500/3*550
Pa=3945.02/1650
Pa= 2.3910 Psi
P=14.233
So according to design thickness is not Appropriate .
Please check this Calculation and let me know where I m wrong as i think some where i m doing some mistake .. or may be full calculation wrong ..
Hope to get vice reply soon ..
This is my First Post .
Regards
Varun
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